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3 years ago

A statement that is true from a rhombus

Mathematics

1 answer:

Talja [164]3 years ago

8 0

A rhombus has two sets of parallel sides. A rhombus has two pairs of angles

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Determine if the triangles are congruent by HL, SAS, SSS, AAS, or

Tom [10]

Asa. the side is in the middle of the angles

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3 years ago

A number cube is rolled and a coin is flipped.

KengaRu [80]

Answer:

Event 1: Rolling a number cube has 6 possible outcomes. Event 2: Flipping a coin has 2 possible outcomes. There are 12 possible outcomes.

3 0

3 years ago

Read 2 more answers

How to do question 1?Had no idea how to do both parts

givi [52]

$y=\dfrac{\ln x}{3x-6}$

Differentiate both sides with respect to $x$ :

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}$

When $x=1$ , you have

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}=\dfrac{-3}9=-\dfrac13$

For part (b), we now assume that $x$ and $y$ are functions of an independent variable, which we'll call $t$ (for time). Now differentiating both sides with respect to $t$ , we have

$\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}\dfrac{\mathrm dx}{\mathrm dt}$

where the chain rule is used on the right side. We're told that $y$ is decreasing at a constant rate of 0.1 units/second, which translates to $\dfrac{\mathrm dy}{\mathrm dt}=-0.1$ . So when $x=1$ , you have

$-0.1=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}\dfrac{\mathrm dx}{\mathrm dt}$
$-0.1=-\dfrac13\dfrac{\mathrm dx}{\mathrm dt}$
$\dfrac{\mathrm dx}{\mathrm dt}=0.3$

where the unit is again units/second.

6 0

3 years ago

Learning Task 1 4/625 11. 796 A. Simplify the radical expressions 1. V63 6. V24 2. 48 7. 781 3. 775 8. V128 4. 99 9. 340 5. 92 1

kompoz [17]

Question:

Simplify the radical expressions

$1.\ \sqrt{63$ $2.\ \sqrt{48$ $3.\ \sqrt{75$ $4.\ \sqrt{99$ $5.\ \sqrt{92$

$6.\ \sqrt[3]{24}$ $7.\ \sqrt[3]{81}$ $8.\ \sqrt{128}$ $9.\sqrt[3]{40}$ $10.\ \sqrt[3]{135}$

Answer:

$\sqrt{63}= 3 \sqrt7$

$\sqrt{48} = 4\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$\sqrt{99} = 3 \sqrt{11$

$\sqrt{92} = 2\sqrt{23$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$\sqrt{128} = 8 \sqrt{2}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

Step-by-step explanation:

$1.\ \sqrt{63$

Express 63 as 9 * 7

$\sqrt{63}= \sqrt{9 * 7$

Split:

$\sqrt{63}= \sqrt{9} * \sqrt7$

$\sqrt{63}= 3 * \sqrt7$

$\sqrt{63}= 3 \sqrt7$

$2.\ \sqrt{48$

Express 48 as 16 * 3

$\sqrt{48} = \sqrt{16*3}$

Split

$\sqrt{48} = \sqrt{16}*\sqrt{3}$

$\sqrt{48} = 4*\sqrt{3}$

$\sqrt{48} = 4\sqrt{3}$

$3.\ \sqrt{75$

Express 75 as 25 * 3

$\sqrt{75} = \sqrt{25*3}$

Split

$\sqrt{75} = \sqrt{25}*\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$4.\ \sqrt{99$

Express 99 as 9 * 11

$\sqrt{99} = \sqrt{9} * \sqrt{11}$

Split

$\sqrt{99} = 3 \sqrt{11$

$5.\ \sqrt{92$

Express 92 as 4 * 23

$\sqrt{92} = \sqrt{4} * \sqrt{23$

$\sqrt{92} = 2* \sqrt{23$

$\sqrt{92} = 2\sqrt{23$

$6.\ \sqrt[3]{24}$

Express 24 as 8 * 3

$\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}$

Express 8 as 2^3

$\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$7.\ \sqrt[3]{81}$

Express 81 as 27 * 3

$\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}$

Express 27 as 3^3

$\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$8.\ \sqrt{128}$

Express 128 as 64 * 2

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

$9.\sqrt[3]{40}$

Express 40 as 8 * 5

$\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}$

$\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$10.\ \sqrt[3]{135}$

Express 135 as 27 * 5

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

Express 27 as 3^3

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

4 0

3 years ago

How to multiply Decimals by power of 10?

Ilia_Sergeevich [38]

Answer:

maybe this well help

Step-by-step explanation:

When you multiply a decimal by a power of 10, simply move the decimal place to the right as many places as there are 0s in the power of 10. When you divide a decimal by a power of 10, simply move the decimal place to the left as many places as there are 0s in the power of 10.

5 0

3 years ago

Read 3 more answers