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vovangra [49]
2 years ago
7

HELP ME PLEASE AHHHHH!!!

Mathematics
1 answer:
FrozenT [24]2 years ago
5 0
If im not wrong...D.... would be the answer
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Ayo help me please I give u 10 points
slavikrds [6]

Answer:

A and D

Step-by-step explanation:

Moving the line left would be moving it onto the y - axis

Therefore the solution would be any point that starts with 0

So (0, 1), (0, 2), (0, -9), etc.

3 0
2 years ago
What is the size of the picture reducing it by 1/25 original size 75 by 50
Svetradugi [14.3K]
50/1 * 1/25 = 50/25 = 2

75/1 * 1/25 = 75/25 = 3

The reduced painting is 2cm x 3cm
5 0
3 years ago
3,6,11,18,27,38
MakcuM [25]

Answer:  The pattern is x^2+2

where x is the term number

Example: the 5th term is 27 because x = 5 leads to x^2+2 = 5^2+2 = 27

=================================================

Explanation:

  • The jump from 3 to 6 is +3
  • The jump from 6 to 11 is +5
  • The jump from 11 to 18 is +7
  • The jump from 18 to 27 is +9
  • The jump from 27 to 38 is +11

The pattern of jumps is: 3, 5, 7, 9, 11

Those increments are going up by 2 each time.

Since we have a consistent pattern of increments, this means that the sequence follows a quadratic model.

Quadratics are stuff like x^2+7x+10 or 3x^2-7. The leading term has an exponent of 2.

-----------

If x is the term number and y is the term itself, then we have these points

(1,3)

(2,6)

(3,11)

(4,18)

(5,27)

(6,38)

The x coordinates increase by 1 each time. The y coordinates are the terms given by your teacher.

Pick exactly 3 of those points. I'll pick the first 3.

Why 3? Because we'll have 3 unknowns to solve for, in which we'll need 3 equations.

  • Plug (x,y) = (1,3) into y = ax^2+bx+c, then simplify. You should get the equation a+b+c = 3
  • Repeat for (x,y) = (2,6) and you should get 4a+2b+c = 6
  • Repeat for (x,y) = (3,11) and you should get 9a+3b+c = 11

-----------

We have this system of equations

\begin{cases}a+b+c = 3\\ 4a+2b+c = 6\\9a+3b+c = 11\end{cases}

There are a number of methods to solve this system. Substitution is what I'll go for.

Solve the first equation for c

a+b+c = 3

c = 3-a-b

Then use substitution.

4a+2b+c = 6

4a+2b+(3-a-b) = 6

3a+b+3 = 6

3a+b = 6-3

3a+b = 3

and

9a+3b+c = 11

9a+3b+(3-a-b) = 11

8a+2b + 3 = 11

8a+2b = 11-3

8a+2b = 8

We now have this reduced system of equations.

\begin{cases}3a+b = 3\\8a+2b = 8\end{cases}

I'll skip the steps as this solution is getting very lengthy as it is. The basic idea is to use substitution again. You should find that a = 1 and b = 0 form the solution set here.

Use those values to find c

c = 3-a-b

c = 3-1-0

c = 2

-----------

To summarize the previous section, we have these solutions:

a = 1, b = 0, c = 2

Therefore the equation y = ax^2+bx+c becomes y = 1x^2+0x+2 aka y = x^2+2. This lets us find any term.

Let's test it out.

  • If x = 1, then y = x^2+2 = 1^2+2 = 3
  • If x = 2, then y = x^2+2 = 2^2+2 = 6
  • If x = 3, then y = x^2+2 = 3^2+2 = 11

And so on. I'll let you test the other x values (4 through 6).

Another way to confirm the answer is to subtract 2 from each item in the original set {3,6,11,18,27,38} and you'll end up with {1,4,9,16,25,36}. This is the list of perfect squares. It shows that term x is simply x^2 but add on 2 so things are adjusted accordingly.

Side note: you can use a tool like GeoGebra or WolframAlpha to quickly solve the system of equations. However, I recommend it only as a means to check your answer rather than do the work for you.

7 0
2 years ago
If four times the sum of a number and 3 is divided by 2, the quotient is 0: find the number
AveGali [126]

The other number is -3.

Step-by-step explanation:

Step 1; First we develop formulae for the given information. A number is added with 3 and the resulting sum is multiplied by 4. This number is then divided by 2 and the quotient is 0. Assume the unknown number is x, then the given information is as follows

The quotient of \frac{4(x+3)}{2} is 0. So \frac{4(x+3)}{2} = 0.

Step 2; Now we solve the above equation. The denominator is taken to the RHS and the RHS remains zero.

\frac{4(x+3)}{2} = 0, 4(x+3)= 0, 4x+ 12 = 0, 4x = -12, x = \frac{-12}{4} = -3.

So the other number is -3.

3 0
3 years ago
List P contains m numbers; list Q contains n numbers. If the two lists are combined to produce list R, containing m + n numbers,
Anarel [89]

Answer: YES

Step-by-step explanation:

We need to write out the expressions

P= {m}

Q= {n}

R= {m+n}

If 2m=n then we can say;

P= {½n} Q= {n} & R= {³/²n}

It is obvious that the smaller number in Q is greater than the largest number in P

We can make some assumptions.

Let n= (x,y,z)

Consequently,

P={½x,½y,½z} Q={x,y,z} and R= {1.5x,1.5y,1.5z}

Therefore the median will be the middle element,

Median of P= ½y

Median of Q = y

Median of R = 1.5y

And 1.5y>1.5y

Then we can agree that the median of R is greater than the median of both P and Q

5 0
3 years ago
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