Answer:
m∠R = 123°
m∠S = 91°
Step-by-step explanation:
The measure of an inscribed angle is 1/2 the measure of the intercepted arc
m of arc QRS = 2 m∠P = 2(57) = 114
Now m of arc SPQ = 360 - 114 = 246
So, m∠R = 1/2(246) = 123
m of arc RSP = 2 m∠Q = 2(89) = 178
m of arc PQR = 360 - 178 = 182
m∠S = 1/2(182) = 91
first off let's notice that the height is 11 meters and the volume of the cone is 103.62 cubic centimeters, so let's first convert the height to the corresponding unit for the volume, well 1 meters is 100 cm, so 11 m is 1100 cm.
Answer:
12 in
Step-by-step explanation:
the scale factor of the enlarged frame is found by comparing the widths
original width : enlarged width = 2 : 6 = 1 : 3
That is 3 times the original width , then
enlarged height = 4 × 3 = 12 in
Answer A
For ease convert both into ounces.
Gross = (11x16) + 5 = 181 ounces
Packaging = (1x16) + 15 = 31 oz.
Now subtract Packaging from Gross
181 - 31 = 150 oz.
Divide by 16 to get pounds
150/16 = 9.375 - hence 9 lb.
and multiply 16 by .375 for ounces
0.375 x 16 = 6 oz.
Thus A : 9lb 6 oz
Answer:
Area of pathway = 10.375 unit²
Step-by-step explanation:
Given - Peter has built a gazebo, whose shape is a regular heptagon, with
a side length of 1 unit. He has also built a pathway around the
gazebo, of constant width 1 unit, as shown below.
To find - Find the area of the pathway.
Proof -
Central angle = = 51.43°
Now,
Central angle / 2 = = 25.71°
And
height = = 1.038
Now,
Inner area of gazebo = 7··1·(1.038) = 3.634 unit²
Outer area of gazebo = ()²·(3.364) = 14.009 unit²
∴ we get
Area of pathway = Outer area - Inner area
= 14.009 - 3.634
= 10.375 unit²
⇒Area of pathway = 10.375 unit²