Answer: It is verified by testing it. If the data supports the hypothesis, then we consider the hypothesis to be verified and true. If however, the data does not support the hypothesis or refutes it, then the hypothesis is in trouble, and we have to come up with a different hypothesis to explain the observations.
Explanation:
Answer:
Goldman is a psychotherapist who follows the psychodynamic perspective. When treating a patient for a fear of spiders, Dr. Goldman <u>first has to assists the patient in identifying the unconscious roots of the fear.</u>
Explanation:
The first thing that Dr. Goldman has to do as a psychotherapist to help a patient with a fear of spiders is work with the person to try to find the reason why the patient is scare of spiders and what has provoked this fear. The cause is something that is repressed and operating on a subconscious level, if not, it would be hard for the person to deal with this fear and the cause in an everyday basis, with the help from the therapist the patient can work on this subconscious things and tolerate them.
Answer:
there is no diagram but
ACTTG-TGAAC
TGAAC-ACTTG
so a and b would be complimentary
Answer:
B
Explanation:
It would be a mutation in a native bacteria.
Answer:
120 white individuals
30 yellow individuals
10 green individuals
Explanation:
Available data:
- Dominant epistasis: Phenotypic frequencies 12:3:1
- W allele codes for a dominant white phenotype
- w allele codes for a colored squash
- Y allele codes for a dominant yellow phenotype
- y allele codes for a recessive green phenotype
- W allele will always mask the phenotype produced by Y or y alleles
Dihybrid Cross
Parental) WwYy x WwYy
Gametes) WY Wy wY wy
WY Wy wY wy
Punnet Square)
WY Wy wY wy
WY WWYY WWYy WwYY WwYy
Wy WWYy WWyy WwYy Wwyy
wY WwYY WwYy wwYY wwYy
wy WwYy Wwyy wwYy wwyy
F1 Phenotypic Frequency)
White phenotype: 12/16 = 120 individuals
Yellow phenotype: 3/16 = 30 individuals
Green Phenotype: 1/16 = 10 individuals
To know how many offspring are expected to have the white, yellow, and green phenotypes, you can perform a three simple rule. This is:
16 ------- 160 offspring
12 White ------- X = 120 offspring
3 Yellow ------- X= 30 offspring
1 Green --------X = 10 offspring
