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nikitadnepr [17]
3 years ago
12

If it is 3:00 p.m. in the Pacific Time Zone, the time in the Eastern Time Zone will be _____. 4:00 p.m. 5:00 p.m. 6:00 p.m. 12:0

0 p.m.
Biology
2 answers:
Serggg [28]3 years ago
8 0
6:00 Eastern time there is a three hour difference
dimaraw [331]3 years ago
6 0
 the correct answer would be 6:00pm 

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Condensation, which is the process by which water vapor is changed back into liquid water. Then precipitation occurs.

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How does the contractile vacuole in a single-celled organism function to maintain homeostasis?
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Suppose two independently assorting genes are involved in the pathway that determines fruit color in squash. These genes interac
makvit [3.9K]

Answer:

100% yellow fruit color, Yyww.

Explanation:

<u>Available data</u>:

  • two independently assorting genes
  • the W allele codes for a dominant white phenotype
  • w allele codes for a colored squash
  • The allele Y codes for a dominant yellow phenotype
  • the allele y codes for a recessive green phenotype
  • The phenotypes from the first locus will always mask the phenotype produced by the second locus if the dominant allele (W) is present at the first locus. This masking pattern is known as dominant epistasis

Epistasis means "interruption" and refers to interactions between genes located in different loci in the same chromosome. An “epistatic gene” can alter, influence, or suppress the expression of a "hypostatic gene". When the epistatic gene is dominant, the interaction is known as "dominant epistasis".

W suppresses the expression of Y and y, this means that whenever W is present, the fruit is white. If W <u>is not</u> present, the fruit color can be expressed.

So, the proposed cross in the present problem occurs between a green fruited individual and yellow fruited individual, which suggests that W is absent.

<em>Genotype for Green fruit: yyww</em>

<em>Genotype for purebred Yellow fruit: YYww</em>

Cross:

Parental) YYww    x    yyww

Gametes) Yw  Yw  Yw  Yw  yw  yw  yw  yw

Punnet square)    Yw       Yw       Yw      Yw

                 yw    Yyww  Yyww  Yyww  Yyww

                 yw    Yyww  Yyww  Yyww  Yyww

                 yw    Yyww  Yyww  Yyww  Yyww

                 yw    Yyww  Yyww  Yyww  Yyww

F1) 100% Yellow fruited plants, Yyww

As these two genes assort independently, we can also represent the cross for each gene by separate, like this:

For w gene:

Parental) ww  x  ww

Gametes) w w w w

Punnet square)  w     w

                 w     ww   ww

                 w      ww  ww

F1) 4/4 or 100% colored-fruits

For Y gene:

Parental) YY  x  yy

Gametes) Y Y y y

Punnet square)  Y     Y

                 y     Yy     Yy

                 y     Yy     Yy

F1) 4/4 or 100% yellow fruits, Yy.

3 0
3 years ago
Use the probability method to calculate the genotypes and genotypic proportions of a cross between AABBCc and Aabbcc parents.
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For this, you need to use Punnett squares.

You know the genotype of the parents, and for the cross, you need to separate into two alleles, both genes.

AABBCc divided like ABC and ABc.

Aabbcc divided like Abc and abc.

Now you can cross them, and all probabilities will be:

AABbCc, AaBbCc, AABbcc and AaBbcc

So, you could say 25% of the offspring will be AaBbCc, 25% AaBbcc, 25% AABbCc, and 25% AABbcc

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