What is the half of 12 take that and - it with 12
If Keith is represented by x, and Joe is three less than Keith, Troy is represented by x-3.
Then, we know that Joe exercises for twice the amount of time as Troy, we multiply the expression for Joe by two.
Keith = x
Troy = x-3
Joe = 2(x-3)
Answer:
by multiplying $2.52 by 4
Step-by-step explanation:
Answer:
x = ![\frac{15}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B8%7D)
<u><em>OR</em></u>
x = ![1 \frac{7}{8}](https://tex.z-dn.net/?f=1%20%5Cfrac%7B7%7D%7B8%7D)
Step-by-step explanation:
![\frac{x}{3} = \frac{5}{8}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B3%7D%20%3D%20%5Cfrac%7B5%7D%7B8%7D)
<em>Cross Multiplying</em>
x × 8 = 5 × 3
8x = 15
<em>Dividing both sides by 8</em>
x = ![\frac{15}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B8%7D)
<u><em>OR</em></u>
x = ![1 \frac{7}{8}](https://tex.z-dn.net/?f=1%20%5Cfrac%7B7%7D%7B8%7D)
The answer is D.<span>Subtract 9 from both sides, because 9 is positive, so you need to subtract.</span>