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irakobra [83]
2 years ago
7

* ANSWER PLS TY!! * Find the surface area of this cone.

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
6 0

Answer:

<h2>200 \: \pi</h2>

Step-by-step explanation:

Given,

R = 8 m

H = 15 m

Slant height :

=  \sqrt{ {r}^{2}  +  {h}^{2} }

=  \sqrt{ {(8)}^{2} +  {(15)}^{2}  }

=  \sqrt{64 + 225}

=  \sqrt{289}

=  \sqrt{ {(17)}^{2} }

= 17 \: m

Now, Finding the surface area of the cone:

\pi \: r(r + s)

Plugging the values:

= \pi \:  \times 8(8 + 17)

= 8\pi \:  \times 25

= 200 \: \pi

Hope this helps...

Good luck on your assignment...

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Answer:

18 pencils

Step-by-step explanation:

1/2 dozen:6

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7 0
3 years ago
Can anyone help me solve this Algebra 2 Problem, i literally cant figure it out
Andrews [41]

Answer:

Zeros : 1 , -1, 3

Degree : 4

End Behaviour : At x-> ∞ f(x) -> ∞ and x->-∞ f(x) -> ∞

Y - intercept : -3

Extra Points: (0,-3), (2,-3)

Step-by-step explanation:

f(x) = 0 to find the zeros

Therefore (x+1)(x-1)^{2} (x-3) = 0

Clearly x = -1,1,3

Here 1 is a repeating root as it is (x-1)²

Degree is highest power of x in f(x)

Clearly it is x*x²*x = x⁴ is the maximum power of x

Thus degree is 4

Looking at end behavior we substitute x->∞ and x-> -∞

Clearly f(x)>0 as all terms are positive and f(x)->∞

Similarly when x->-∞

f(x)>0 as 2 terms are -ve and their product is positive thus f(x)-> ∞

Y-Intercept is f(0)

f(0) = (0+1)(0-1)²(0-3) = 1*1*-3 = -3

Thus Y-Intercept is -3

Substitute x = 0 , 2 for extra points

Thus f(0) = -3

and f(2) = -3

Thus points on the graph (0,-3), (0,2)

We can use all this information to draw a graph remember that 1 is a repeating root so that will be a point of minima. The graph is a parabola that passes through x-axis at x = -1, 3.

5 0
3 years ago
What times 2 equels -108
Igoryamba
-54 i think is the answer 
8 0
3 years ago
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Can I have the answers to this? Thanks​
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7 0
3 years ago
Find the GCF of 48 and 42​
ivann1987 [24]

Answer:

The gcf of 42 and 48 can be obtained like this:

The factors of 42 are 42, 21, 14, 7, 6, 3, 2, 1.

The factors of 48 are 48, 24, 16, 12, 8, 6, 4, 3, 2, 1.

The common factors of 42 and 48 are 6, 3, 2, 1, intersecting the two sets above.

In the intersection factors of 42 ∩ factors of 48 the greatest element is 6.

Therefore, the greatest common factor of 42 and 48 is 6.

Taking the above into account you also know how to find all the common factors of 42 and 48, not just the greatest.

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3 0
3 years ago
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