Have you learned matrices yet? I'm going to use that to solve these, please refer to the photos.
I solved the system by using a matrix calculation. The work always needs to be shown and you do that by setting up the matrix like in the first photo and also writing out all your equations. In a TI calculator, to do this you press 2ND-X^-1,GO TO EDIT - [A] - 3×4- now enter the coefficient of the system of equations variables. NOW 2ND MODE- 2ND-X^-1 -GO TO MATH- ALPHA APPS
Now, if you don't know this you may be confuse so after rref([A]) was enter a matrix came up with [1 0 0 -21] in the top row this means x equal -21. So, the next row is y and it came out as [0 1 0 46] so y equals 46 and I'm going to let you figure out what z is by looking at the matrix.
SO... X=-21 Y=46 and Z=-10
Let's Test it
Answer:
Step-by-step explanation:
14) 2x - 10 = 80 {alternate interior angles are equal}
2x = 80 + 10
2x = 90
x = 90/2
x = 45°
15) 3x + 120 = 180 { co interior angles are supplementary}
3x = 180 - 120
3x = 60
x = 60/3
x = 20°
16) 3x + 15 = 135 {corresponding angles are equal}
3x = 165 - 15
3x = 150
x = 150/3
x = 50°
The original answer for that question would be 303.55. The best estimate when you round to the nearest tenth the approximate answer would be 303.6 because the 5 in the hundredths place rounds the 5 in the tenths place to a 6. So the approximate answer would be 303.6....hope this helps.
B
but i have to write more to let me post this so here it is
It contains one significant digit and the rule for this one is that leading zeros in fractions less than one are not significant.