Answer: They are close to each other by 41.03 m^3
Explanation:
From Ideal gas equation, PV = nRT
Where n is negligible
R is gas constant = 8.314 J/mol.k
T = 30 + 273 = 303K
P = 1.02 * 103351.5 = 103351.5 Pascal
Then;
PV = RT
V = P/RT
V = 103351.5/(8.314*303)
V = 41.03m^3
Answer:
89.6 liters
Explanation:
A STP (standard temperature and pressure) ONE mole of any idea gas will occupies 22.4 liters. So,...
4 moles x 22.4 L/mol = 89.6 liters
The pressure of a sample of a gas if the temperature is changed to 127 c while the volume remains constant is calculated using gay lussac law formula
that is P1/T1 = P2/V2
P1 = 100 torr
T1 = 27+273 = 300 k
T2 =127 +273 =400 k
P2=?
by making P2 the subject of the formula
P2=T2P1/T1
=100 x 400/300 = 133.3 torr
Answer:
Explanation:
formula of osmotic pressure is as follows
p= n RT
n is mole of solute per unit volume
If m be the grams of solute needed
m gram = m / 227.1 moles
m / 227.1 moles dissolved in .279 litres
n = m / (227.1 x .279 )
= m / 63.36
substituting the values in the osmotic pressure formula
5.14 = (m / 63.36) x .082 x 298
m / 63.36 = .21
m = 13.32 grams .
Answer:
How many moles KCl in 1 grams? The answer is 0.013413582325
1 mole is equal to 1 moles KCl, or 74.5513 grams.
447.3078 is the answer
Explanation:
<em>~Cornasha_Weeb</em>
