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Harrizon [31]
3 years ago
7

What are the different areas of an electron cloud called?

Chemistry
1 answer:
kifflom [539]3 years ago
5 0
They are called "energy levels".
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If a helium filled ballon has a volume of 3.4l at 25°c and 1.18atm., what is its volume at STP?​
vladimir2022 [97]

Answer:

3.711 L

Explanation:

The formula you need to use is the following:

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\

3.4L / 298 K = V2 / 273 K

V2 = 3.711 L

5 0
2 years ago
Pb(SO4)2 + 4 LiNO3 → Pb(NO3)4 + 2 Li2SO4
Anvisha [2.4K]

Answer:

4.5 moles of lithium sulfate are produced.

Explanation:

Given data:

Number of moles of lead sulfate = 2.25 mol

Number of moles of lithium nitrate = 9.62 mol

Number of moles of lithium sulfate = ?

Solution:

Chemical equation:

Pb(SO₄)₂ + 4LiNO₃      →     Pb(NO₃)₄ + 2Li₂SO₄

Now we will compare the moles of lithium sulfate with lead sulfate and lithium nitrate.

                       Pb(SO₄)₂        :         Li₂SO₄

                            1                :             2

                          2.25           :          2/1×2.25 = 4.5 mol

                       LiNO₃            :             Li₂SO₄

                           4                :                2

                           9.62           :             2/4×9.62 = 4.81 mol

Pb(SO₄)₂  produces less number of moles of Li₂SO₄ thus it will act as limiting reactant and limit the yield of  Li₂SO₄.      

7 0
3 years ago
Indirect costs incurred in a manufacturing environment that cannot be traced directly to a product are treated as a.product cost
Alisiya [41]

Answer:

C. product costs and expensed when the goods are sold

Explanation:

3 0
3 years ago
Explain where the water that collects on the outside of a cold drink on a hot day comes from.
krok68 [10]

Answer:

It is because water molecules in the air condensed on to the container of the drink.

Explanation:

The way this works is the water molecules outside are hot and in the gas state, so when they come into contact with the cold side of the container they lose energy due to heat transfer between the molecules and the container, becoming a liquid on the side of the drink.

4 0
3 years ago
A 20.0g sample of metal with a specific heat of 5 J/(g°C) raised it's initial temperature to 40.0 when 500J heat was added. What
slavikrds [6]

The initial temperature of the metal = 35 °C

<h3>Further explanation</h3>

Heat can be formulated :

Q = m . c . ΔT

Q = heat, J

c = specific heat, J/g C

ΔT = temperature, °C

m = 20 g

c = 5 J/(g°C)

Q = 500 J

T₁ = 40 C

the initial temperature :

\tt \Delta t(T_2-T_1)=\dfrac{Q}{m.c}\\\\40-T_1=\dfrac{500}{20.5}\\\\40-T_1=5\\\\T_1=35^oC

3 0
2 years ago
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