<u>Answer:</u> The mass percent of water in the original air sample is 4.16 %
<u>Explanation:</u>
We are given:
Volume of moist air = 12.0 L
Volume of dry air = 11.50 L
Volume of water lost = (12.0 - 11.50) L = 0.50 L
Here, the percent by mass ratio will be equal to the percent by volume ratio as the number of moles is directly related to the volume.
To calculate the volume percentage of water in the air, we use the equation:
Putting values in above equation, we get:
Hence, the mass percent of water in the original air sample is 4.16 %
Explanation:
In this reaction, the reactants are Li and N2. The product is Li3N
So we have;
Li + N2 → Li3N
Upon balancing, we have;
6Li + N2 → 2 Li3N
The sum of the coefficients is 6 + 1 + 2 = 9
Answer:
wavelength.. meter
frequency.... Hertz (cycle per second)
energy.... Joule
Answer:
The answer is "
"
Explanation:
We arrange oxoacids to decrease the intensity of acids in this question. Or we may conclude all this from strongest to weakest acids they order oxoacids, that's why above given order is correct.
The answer is C. sugar water. Sugar can dissolve in water completely and form the solution. While other three are all heterogeneous mixture.
