Empirical formula is the simplest ratio of whole numbers of components in a compound
calculating for 100 g of compound
C H O
mass 64.27 g 7.19 g 28.54 g
number of moles 64.27 g / 12 g/mol 7.19 g/1 g/mol 28.54 g / 16 g/mol
= 5.356 mol = 7.19 mol = 1.784 mol
divide by least number of moles
5.356 / 1.784 7.19 / 1.784 1.784 / 1.784
= 3.002 4.03 = 1.000
rounded off to nearest whole number
C - 3
H - 4
O - 1
empirical formula - C₃H₄O
mass of empirical formula = 12 g/mol x 3 + 1 g/mol x 4 + 16 g/mol x 1 = 56 g
molecular mass = 168.19 g/mol
molecular formula is the actual ratio of elements making up the compound
number of empirical units = molar mass of molecule / empirical mass
empirical units = 168.19 g/mol / 56 g = 3.00
there are 3 empirical units making up the molecular formula
molecular formula = 3 x C₃H₄O
molecular formula = C₉H₁₂O₃
Monkey is good and that is all their it to it
Answer:
b. a new gas is observed in the form of bubbles
Explanation:
The only statement that was evidence of a chemical reaction is a new gas is observed in the form of bubbles Any time a new substance is created, a chemical reaction has taken place.
The balanced equations for the formation of potassium suberate from cyclooctene are;
3KMnO4 + 3C8H18 + 4H2O --> 3C8H17(OH)2 + 2MnO2 + 2KOH and
3C8H14(OH)2 + 6KMnO4 ----> 3KCOO(CH2)6 COOK + 6MnO2 + 6H20
<h3>What is potassium suberate ?</h3>
The compound potassium suberate is obtained from cyclooctene. The first step in the process is the oxidation of cyclooctene using potassium permanganate as follows;
3KMnO4 + 3C8H18 + 4H2O --> 3C8H17(OH)2 + 2MnO2 + 2KOH
This is followed by the production of potassium suberate from the reaction equation;
3C8H14(OH)2 + 6KMnO4 ----> 3KCOO(CH2)6 COOK + 6MnO2 + 6H20
Learn more about potassium suberate: brainly.com/question/8507057?
