All categories

3 years ago

a 17.0 g sample of ammonia contains 14.0 g of nitrogen and 3.0 g of hydrogen . what is the mass % of hydrogen in ammonia

Chemistry

1 answer:

lina2011 [118]3 years ago

4 0

Answer:

% age of hydrogen = 17.65%

Explanation:

Given data:

Mass of ammonia = 17.0 g

Mass of hydrogen = 3.0 g

Mass of nitrogen = 14.0 g

Percentage of hydrogen = ?

Solution:

Formula:

% age of hydrogen = mass of hydrogen / mass of ammonia × 100

Now we will put the values:

% age of hydrogen = 3.0 / 17.0 × 100

% age of hydrogen = 17.65%

For oxygen:

% age of hydrogen = mass of hydrogen / mass of ammonia × 100

Now we will put the values:

% age of hydrogen = 14/ 17.0 × 100

% age of hydrogen = 82.35%

Total percentage = 17.65% + 82.35%

Total percentage = 100%

You might be interested in

Which element is a gas at STP?<br> 1)sulfur<br> 2)xenon<br> 3)potassium<br> 4)phosphorus

natulia [17]

I believe the answer is xenon

4 0

3 years ago

Read 2 more answers

Ethan is investigating a snails response to stimuli. He put the following substances on each corner of a paper towel; syrup,lemo

olga nikolaevna [1]

There doesn't seem to be a clear answer, it is placed in the center when it's substances is on the corners it doesn't give anything else

4 0

3 years ago

Read 2 more answers

How many grams of sulfur are required in the preparation of 35.7 moles of sulfur dioxide Sg + O2 SO2

lidiya [134]

S+O_2-->SO_2

Its balanced already

1 mol SO_2 require 1 mole sulphur
35.7moles require 35.7mol sulphur

Mass of S

35.7(32)
1142.4g

6 0

2 years ago

A 5.00-mL sample of blood was treated with trichloroacetic acid to precipitate proteins. After centrifugation, the resulting sol

Anarel [89]

Explanation:

According to the Beer-lambert' s law,

Absrobance = absrobptitvity × lenght × concentration

So, if we will plot a graph between absrobance and concentration then we will obtain a straight line

Hence, formula to calculate slope of the graph is as follows.

The slope of graph = $\frac{\text{difference in absrobance at two points}}{\text{difference in concentrations at those points}}$

The given data is as follows.

$A_{1}$ = 0.412 (first point)

$A_{2}$ = 0.642 (second point)

$C_{1}$ = 0.240 ppm (first point)

$C_{2}$ = 0.475 ppm (second point)

Hence, putting these values into the above formula we will calculate the value of slope as follows.

Slope = $\frac{\text{difference in absrobance at two points}}{\text{difference in concentrations at those points}}$

= $\frac{0.642 - 0.412}{0.475 - 0.240}$

= $\frac{0.23}{0.235}$

= 0.978

It is known that for the graph, line equation can be written as follows.

y = mx + c ........... (1)

where, C = intercept

m = slope

Hence, calculate the value of intercept as follows.

0.412 = $0.24 \times 0.978$ + c

c = 0.178

As it is given that the absorbance values 0.454 (the y-axis value). Therefore, putting this value into equation (1) we get the following.

y = mx + c

0.454 = $x \times 0.978$ + 0.178

0.276 = 0.978x

x = 0.282 ppm

Thus, we can conclude that the concentration of Pb in the given sample is 0.282 ppm.

3 0

3 years ago

Calculate the molarity of a solution made by dissolving 4.0 g of calcium bromide, CaBr2, in enough water to give 200 mL of solut

Troyanec [42]

Answer:

0.1 M

Explanation:

Molarity = number of moles / litres of solution.

4 g of calcium bromide = 0.02 mol

(found by dividing 4 g by the atomic mass of CaBr2, which is 199.886)

200 mL of solution = 0.2 litres

Molarity = 0.02 mol / 0.2 L = 0.1 M

8 0

3 years ago