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NikAS [45]
3 years ago
9

Based on your observations from the glowing splint test with oxygen gas, briefly explain why liquid oxygen is a very hazardous s

ubstance
Chemistry
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

liquid oxygen is highly flammable

Explanation:

near any source of heat. liquid oxygen can explode to flames thus being hazardous

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Liquid, liquids have a definite volume but can take the shape of whatever container holds them.
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What words do you use in a hypothesis
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Answer:

"If________, then _______ will happen because ________.

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A container of gas has a volume of 3.5 L and a pressure of 0.8 atm. Assuming the temperature remains constant, what volume of ga
vovikov84 [41]
<h3>Answer:</h3>

5.6 L

<h3>Explanation:</h3>

We are given;

  • Initial volume, V1 = 3.5 L
  • Initial pressure, P1 = 0.8 atm
  • Final pressure, P2 = 0.5 atm

We are required to calculate the final volume;

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  • That is; P α 1/V
  • Mathematically, P=k/V
  • At two different pressure and volume;

           P1V1 = P2V2

In this case;

Rearranging the formula;

V2 = P1V1 ÷ P2

     = (0.8 atm × 3.5 L) ÷ 0.5 atm

    = 5.6 L

Therefore, the resulting volume is 5.6 L

7 0
3 years ago
Add oxidation numbers to the following reaction: 2 H3PO4 (aq) + 2 Cr(s) → 2 CrPO4 (aq) + 3 H2(g). Identify the atom that is oxid
rewona [7]

The atom that is oxidized : Cr

The oxidizing agent : H₃PO₄

<h3>Further explanation</h3>

Reaction

2 H₃PO₄ (aq) + 2Cr(s) → 2 CrPO₄ (aq) + 3H₂(g)

Atoms undergoing a reduction reaction (decrease in oxidation number) and an oxidation reaction (increase in oxidation number)

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H⁺(in H₃PO₄) =+1

H₂=0

  • Oxidation (0 to +3)

Cr = 0

Cr³⁺(in CrPO₄ )

the oxidizing agent.⇒which undergoes a reduction reaction and oxidizes another compound/element : H₃PO₄

3 0
3 years ago
Carbon has four valence electrons, and oxygen has six valence electrons. If carbon and oxygen bond covalently, which of the foll
IRISSAK [1]
According to data the structures are as drawn below. 
Lewis structure is drawn by adding valence electrons of all elements present in a given compound.
In this case,
6 + 6 + 4 = 16 valence electron
secondly, the central atom is drawn in center and other outside, like carbon in center.
Then single bonds are drawn to connect the central atom to side atoms and 2 electrons for each single bonds are subtracted from total electrons, in this case 16-4=12, these 12 electrons are added to the most electronegative atoms, in this case to oxygen atoms. After that changes are made in a uch a way that each atom gets a complete octet number (8 electrons). 
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8 0
4 years ago
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