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gtnhenbr [62]
3 years ago
10

How many photons are produced in a laser pulse of 0.364 J at 477 nm?

Chemistry
1 answer:
Luda [366]3 years ago
7 0

Answer:

1.00 × 10¹⁸

Explanation:

1. Calculate the <em>energy of one photon</em>

The formula for the energy of a photon is

<em>E</em> = <em>hc</em>/λ  

<em>h</em> = 6.626 × 10⁻³⁴ J·s; <em>c</em> = 2.998 × 10⁸ m·s⁻¹

λ = 477 nm = 477 × 10⁻⁹ m                              Insert the values

<em>E</em> = (6.626 × 10⁻³⁴ × 2.998× 10⁸)/(477 × 10⁻⁹)

<em>E</em> = 4.165× 10⁻¹⁹ J

2. Calculate the <em>number of photons</em>

Divide the total energy by the energy of one photon.

No. of photons = 0.418 × 1/4.165 × 10⁻¹⁹      

No. of photons = 1.00 × 10¹⁸

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andrew-mc [135]

Answer:

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7 0
3 years ago
Two 10g blocks, one of copper and one of iron, were heated from 300 K to 400K (a temperature difference of 100 K).
12345 [234]

1) 385 J

2) 450 J

Explanation:

1)

The amount of energy that must be absorbed by a certain substance in order to increase its temperature by \Delta T is given by the equation:

Q=mC\Delta T

where

m is the mass of the substance

C is its specific heat capacity

\Delta T is the increase in temperature of the substance

For the block of copper in this problem, we have:

m = 10 g is the mass

C=0.385 J/gK is the specific heat capacity of copper

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of copper is

Q=(10)(0.385)(100)=385 J

2)

Similarly for the block of iron, the energy absorbed by the iron is given by

Q=mC\Delta T

where

m is the mass of the block of iron

C is its specific heat capacity of iron

\Delta T is the increase in temperature of the block

Here we have:

m = 10 g is the mass of the block

C=0.450 J/gK is the specific heat capacity of iron

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of iron is

Q=(10)(0.450)(100)=450 J

6 0
3 years ago
The organic compound di‑n‑butyl phthalate, C 16 H 22 O 4 ( l ) , C16H22O4(l), is sometimes used as a low‑density ( 1.046 g ⋅ mL
damaskus [11]

Answer:

36.63 Torr

Explanation:

You need to use two expressions, one for pressure and the other with the relation of density and height of the column.

For the pressure:

P = h * d * g  (1)

h is height.

d density

g gravity

The second expression put a relation between the densities and height of the column so:

d1/d2 = h1/h2 (2)

let 1 be the phthalate, and 2 the mercury.

Let's calculate first the relation of density:

d1/d2 = 13.53 / 1.046 = 12.93

Now with the first expression, we can calculate the pressure so:

P = hdg

We have two compounds so,

h1d1g = h2d2g ---> gravity cancels out

From here, we can solve for h2:

h2 = h1*(d1/d2)

replacing:

h2 = 459 / 12.53

h2 = 36.63 mm

1 mmHg is 1 torr, therefore the pressure of the gas in Torr would be 36.63 Torr

8 0
3 years ago
A golf pro has 2100 J of kinetic energy and swings his driver which weighs .75 kg. What is the speed of his swing?
jeka57 [31]

Answer : The correct answer is 74.83 m/s .

The kinetic energy is energy possessed by any mass which is moving or have some speed . It is product of mass and velocity . It is expressed as :

KE = \frac{1}{2}  * m* v^2

Where KE = kinetic energy in J or kg\frac{m^2}{s^2} m = mass in Kg v = speed in m/s²

Unit of KE is Joules (J) .

Givne : KE = 2100 J mass = 0.75 kg v = ?

Plugging value in KE formula =>

2100 J = \frac{1}{2}  * 0.75 Kg * v^2

2100 J = 0.375 Kg * v^2

Dividing both side by 0.375 kg =>

\frac{2100 J}{0.375 Kg}  = \frac{0.375 Kg}{0.375 Kg } * v^2

v^2 = 5600 \frac{m^2}{s^2}

v= 74.83 \frac{m}{s}

8 0
3 years ago
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The diagram below represents reaction of reactant A and reactant B combining to form product C.
OleMash [197]

Answer:B

Explanation:

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