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shepuryov [24]
3 years ago
15

A → B is a first order reaction. Using the data below, what is the half-life in seconds? 0 sec, [A] = 1.22 M 3 sec, [A] = 0.86 M

6 sec, [A] = 0.61 M 9 sec, [A] = 0.43 M 12 sec, [A] = 0.31 M 15 sec, [A] = 0.22 M 18 sec, [A] = 0.15 M
Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

Half-life time is 6s

Explanation:

A first order reaction follows the formula:

ln[A] = ln[A]₀ - kt

Thus, the graph of ln[A] vs t will have as slope -k.

Graphing the given values you will obtain the linear formula:

y = -0.1154x + 0.1994

R² = 0.9997

Thus, slope is -0.1154s⁻¹ and k is:

-k = -0.1154s⁻¹; <em>k = 0.1154</em>s⁻¹

Now, as half-life in a first order reaction is:

t_{1/2} = \frac{ln2}{k}t_{1/2} = \frac{ln2}{0.1154s^{-1}} = 6s

<em>Half-life time is 6s</em>

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Let's consider the following reaction.

4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)

The standard molar entropy of the reaction (ΔS°) can be calculated using the following expression.

ΔS° = ∑np × S°p - ∑nr × S°r

where,

ni are the moles of reactants and products

S°i are the standard molar entropies of reactants and products

ΔS° = 4 mol × S°(NO(g)) + 6 × S°(H₂O(g)) - 4 mol × S°(NH₃(g)) - 5 mol × S°(O₂(g))

ΔS° = 4 mol × 210.8 J/K.mol + 6 × 188.8 j/K.mol - 4 mol × 192.5 J/K.mol - 5 mol × 205.1 J/K.mol

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This is the change in the entropy per mole of reaction.

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How many moles are in 25.90 grams of NaCl
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A dilute solution of bromine in carbon tetrachloride behaves as an ideal-dilute solution. The vapour pressure of pure CCl4 is 33
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Explanation:

The given data is as follows.

     Vapour pressure of pure CCl_{4} = 33.85 Torr

         Temperature = 298 K

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Therefore, calculate the vapor pressure of Br_{2} as follows.      

     Vapour pressure of Br_{2} = mole fraction of Br_{2} x K of Br_{2}

                                    = 0.050 x 122.36 Torr

                                   = 6.118 Torr

So, vapor pressure of Br_{2} is 6.118 Torr .

Now, calculate the vapor pressure of carbon tetrachloride as follows.

     Vapour pressure of CCl_{4} = mole fraction of CCl_{4} x Pressure of CCl_{4}

                                     = (1 - 0.050) × 33.85 Torr

                                     = 32.1575 Torr

So, vapor pressure of CCl_{4} is 32.1575 Torr  .

Hence, the total pressure will be as follows.

                         = 6.118 Torr + 32.1575 Torr

                         = 38.2755 Torr

Therefore, composition of CCl_{4} = \frac{32.1575 Torr}{38.2755 Torr}

                         = 0.8405

Composition of CCl_{4} is 0.8405 .

And, composition of Br_{2} = \frac{6.118 Torr}{38.2755 Torr}

                                                  = 0.1598

Composition of Br_{2} is 0.1598 .

6 0
3 years ago
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