1 answer:
Answer:
0.25feet
Step-by-step explanation:
The equation is not well written. Let the equation of the height be modelled as;
h = -16d²+8d+4
The velocity of the ball is zero at its maximum height.
Velocity = change in displacement/time
v = dh/dd
Differentiate
v = -32d+8
Since dh/dd = v = 0
0 = -32d+8
Add 32d to both sides
0+32d = 8
32d = 8
Divide both sides by 32
32d/32 = 8/32
d = 1/4
d = 0.25feet
Hence the maximum height of the tennis ball is 0.25feet
Note that the modeled equation was assumed. You can apply the same calculation to any equation given
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