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scZoUnD [109]
3 years ago
11

Why does water evaporate more quickly on a hot, dry day than on a hot, humid day?

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0
Because on a hot, humid day there is more water vapor in the air than there would be on a hot, dry day.
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Why estuaries are an important habitat for many marine organisms in comparison to the open ocean?
Alexxandr [17]

Answer:

There are more nutrients available in estuaries. There are more nutrients available in estuaries.

Explanation:

5 0
2 years ago
Calculate the pressure exerted by an book of mass 20kg occupying an area of 2 m square.​
kotykmax [81]

The answer is 100 Pa.

The formula for calculating pressure is :

<u>Pressure = Force ÷ Area</u>

<u />

We are given that :

  • mass = 20 kg
  • area = 2 m²

We also know that :

<u>Force = mass ×g</u>

<u />

So, force will be :

  • F = 20 × 10
  • F = 200 N

Now, we can finally calculate pressure :

  • P = 200 ÷ 2
  • P = 100 Pa
8 0
1 year ago
Liquid<br><br> Describe this state of matter in 3-4 sentences
Law Incorporation [45]

Answer: Liquid has no definite shape but it has definite volume. The particles are free to move over each other but are still attracted to each other. Liquids can be compressed into gas.

Hope this helps :)

4 0
3 years ago
11. The back part of the cerebrum deals with hearing<br><br> True<br><br> False
Sunny_sXe [5.5K]

Answer:

The answer is: True

5 0
2 years ago
A 25.0-mL sample of 0.150 M hydrazoic acid, HN3, is titrated with a 0.150 M NaOH solution. What is the pH after 13.3 mL of base
tamaranim1 [39]

Answer:

pH ≅ 4.80

Explanation:

Given that:

the volume of HN₃ = 25 mL = 0.025 L

Molarity of HN₃ = 0.150 M

number of moles of HN₃ = 0.025 × 0.150

number of moles of HN₃ =  0.00375  mol

Molarity of NaOH = 0.150 M

the volume of NaOH = 13.3 mL = 0.0133

number of moles of NaOH = 0.0133× 0.150

number of moles of NaOH = 0.001995 mol

The chemical equation for the reaction of this process can be written as:

HN_3 + OH- ---> N^-_{3} + H_2O

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water

thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol

Total volume used in the reaction =  0.025 +  0.0133 = 0.0383  L

Concentration of HN_3 = \dfrac{0.001755}{0.0383} = 0.0458 M

Concentration of N^{-}_3 = \dfrac{ 0.001995 }{0.0383} = 0.0521 M

GIven that :

Ka = 1.9 x 10^{-5}

Thus; it's pKa = 4.72

pH =4.72 +  log(\dfrac{ \ 0.0521}{0.0458})

pH =4.72 + log(1.1376)

pH =4.72 + 0.05598

pH =4.77598

pH ≅ 4.80

3 0
3 years ago
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