I can't really answer his if there is no given. However, there are general rules to follow when naming ionic compounds. For example, if the given compound is written as: MgCl₂.
There are two elements that we could find: Mg and Cl. The rule is to write the positive ion first, followed by the negative ion. The individual charges of each element is the subscript of the other. Since Cl has a subscript of 2, then Mg has a charge of +2. Since Mg has a subscript of 1, then Cl has a charge of -2.
Finally, the rule of naming the ionic compound is to name the ions individually in order, but you have to take the suffix -ide (if the charge is -1). Thus, the name of the compound is Magnesium Chloride,
The correct answer is: -3 (minus three)
Explanation:
To find the overall charge, we add electrons and protons. Make sure that you use the negative sign for an electron and positive sign for proton.
There are 10 electrons. It means the charge is "-10"
There are 7 protons. It means the charge is "+7"
Add both of them:
+7 - 10 = -3
Therefore the overall charge on this ion is -3.
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Answer:</h3>
A. 1.4 V
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Explanation:</h3>
We are given the half reactions;
Ni²⁺(aq) + 2e → Ni(s)
Al(s) → Al³⁺(aq) + 3e
We are required to determine the cell potential of an electrochemical cell with the above half-reactions.
E°cell = E(red) - E(ox)
From the above reaction;
Ni²⁺ underwent reduction(gain of electrons) to form Ni
Al on the other hand underwent oxidation (loss of electrons) to form Al³⁺
The E.m.f of Ni/Ni²⁺ is -0.25 V and that of Al/Al³⁺ is -1.66 V
Therefore;
E°cell = -0.25 V - (-1.66 V)
= -0.250V + 1.66 V
= + 1.41 V
= + 1.4 V
Therefore, the cell potential will be +1.4 V
Answer:
2,14 g / ml
Explanation:
Sabemos que el volumen de una sustancia es igual al cambio de volumen del agua cuando el objeto en cuestión se sumerge en el agua.
Dado que el volumen original del agua = 50 ml
Volumen de agua después de sumergir el objeto = 120 ml
Masa del objeto = 150 g
Ahora,
Densidad = masa / volumen
Densidad = 150g / 120-50 ml
Densidad = 150/70 ml
Densidad = 2,14 g / ml