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AlekseyPX
1 year ago
5

fig. 15 shows a simplified diagram of the electrolysis of a molten electrolyte containing lithium chloride. b. Describe how the

electron configuration of each lithium ion changes when it arrives at the cathode. You may draw a diagram to help you answer this question.​

Chemistry
1 answer:
melisa1 [442]1 year ago
8 0

During the electrolysis of the molten lithium chloride, the Lithium ions (Li⁺) at the cathode undergoes reduction, and the electron configuration of lithium becomes 1s²2s¹.

<h3>What is electrolysis?</h3>

Electrolysis can be described as the process in which the electric current is passed through the chemical compound to break them.  In this process, the atoms and ions are interchanged by the addition or removal of electrons.

The ions are allowed to move freely in this process. When an ionic compound is melted or dissolved in water then ions are produced which can move freely.

During the electrolysis of molten lithium chloride, the lithium ions reach the cathode and accept the electrons while chloride ions reach at anode and loss electrons to become chlorine gas.

At anode :  2 Cl⁻ →    Cl₂ + 2e⁻

At cathode:   2 Li⁺   +   2e⁻  →  Li

Learn more about electrolysis, here:

brainly.com/question/12054569

#SPJ1

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what is the balanced equation when copper metal is placed in a solution when platnium ii chloride is placed. what is the equatio
koban [17]

Answer:

Cu~+~PtCl_2->Pt~+~CuCl_2

Explanation:

In this case, we can start with the <u>formula of Platinum (II) Chloride</u>. The cation is the atom at the left of the name (in this case Pt^+^2) and the anion is the atom at the right of the name (in this case Cl^-). With this in mind, the <u>formula would be</u> PtCl_2.

Now, if we used <u>metallic copper</u> we have to put in the reaction only the <u>copper atom symbol</u> Cu. So, we have as reagents:

Cu~+~PtCl_2->

The question now is: <u>What would be the products?</u> To answer this, we have to remember <u>"single displacement reactions"</u>. With a general reaction:

A~+~BC->AB~+~C

With this in mind, the reaction would be:

Cu~+~PtCl_2->Pt~+~CuCl_2

I hope it helps!

5 0
2 years ago
37.9 grams of an unknown substance undergoes a temperature increase of
jenyasd209 [6]

Answer:

1.023 J / g °C

Explanation:

m = 37.9 grams

ΔT = 25.0*C

H = 969 J

c = ?

The equation relating these equation is;

H = mcΔT

making c subject of formulae;

c = H / mΔT

c = 969 J / (37.9 g * 25.0*C)

Upon solving;

c = 1.023 J / g °C

4 0
2 years ago
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4 0
3 years ago
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What is the hydronium ion concentration of a 0.100 M acetic acid solution with Ka = 1.8 × 10-5? The equation for the dissociatio
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Answer:

1.3×10⁻³ M

Explanation:

Hello,

In this case, given the dissociation reaction of acetic acid:

CH_3CO_2H(aq) + H_2O(l) \rightleftharpoons H_3O^+(aq) + CH_3CO_2^-(aq)

We can write the law of mass action for it:

Ka=\frac{[H_3O^+][CH_3CO_2^-]}{[CH_3CO_2H]}

Of course, excluding the water as heterogeneous substances are not included. Then, in terms of the change x due to the dissociation extent, we are able to rewrite it as shown below:

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Thus, via the quadratic equation or solve, we obtain the following solutions:

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Regards.

8 0
3 years ago
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