Ask question

Ask question

All categories

3 years ago

14

37= -3+5(x + 6) slove for x

1 answer:

lions [1.4K]3 years ago

8 0

Step 1: Simplify both sides of the equation.
37
=
−
3
+
5
(
x
+
6
)
37
=
−
3
+
(
5
)
(
x
)
+
(
5
)
(
6
)
(Distribute)
37
=
−
3
+
5
x
+
30
37
=
(
5
x
)
+
(
−
3
+
30
)
(Combine Like Terms)
37
=
5
x
+
27
37
=
5
x
+
27
Step 2: Flip the equation.
5
x
+
27
=
37
Step 3: Subtract 27 from both sides.
5
x
+
27
−
27
=
37
−
27
5
x
=
10
Step 4: Divide both sides by 5.
5
x
5
=
10
5
x
=
2

You might be interested in

Which number has the same value as 28 tens? 28 or 280

KIM [24]

28 because we are talking about TENS meaning there can only be 2 digits

3 0

3 years ago

The price received for a bicycle is given by the equation b = 100 – 10x2, where x is the number of bicycles produced, in million

Alchen [17]

Answer:

I. B. P = – + 40x

II. 1.3

hope this helps! :o)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

This is in integers.<br><br> Q: evaluate (+5)-(+9)-(-7)

creativ13 [48]

can be simplified as 5-9+7=-4+7=3

3 0

3 years ago

Read 2 more answers

Use the cubic model y = 5a3 - 2a2 + a - 45 to find the value of y when x = 4.

Naddik [55]

Assuming 5a3 equals 5a^3, and the same for everything else, you would plug in 4 for a, so 5(4)^3 - 2(4)^2 + 4 - 45, which equals 247.

3 0

3 years ago

Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

4 years ago