Answer:
Explanation:
Evaporation results in cooling because water absorbs heat equal to mass times latent heat of evaporation to get converted into vapor .
latent heat of evaporation of water = 2260 x 10³ J / kg or 2260 J / g
in the evaporation of 1 g of water , heat lost = 2260 J
heat lost per minute = 2260 J
heat lost per second = 2260 / 60
= 37.66 J /s
= 37.66 W
So heat lost by dog in watt = 37.66 W.
Answer:
The answers to the question are
(a) The integer n that describes the harmonic whose frequency is 571 Hz is 5
(b) The length of the tube is 0.75 m.
B. The depth of the well is 7.12 m.
Explanation:
The nth harmonic of a tube with one end closed is given by
and the next harmonic is
Therefore ividing the first two equations by each other we have
from which n =
Therefore the interger that descries the first harmonic is
n = = 5
(b) We have the length of the pipe given by
L = 5λ/4 but λ = v/f = 343/571 = 0.6 ∴ L = 5*0.6/4 = 0.75 m
B. From n = we have
n for the 36.1 Hz frequency
n = = 3 Therefore λ = v/f = 343/36.1 = 9.5 m
L = 3*λ/4 = 3*9.5/4 = 7.12 m
The well is 7.12 m deep
Answer:
I think d is the answer haha
Answer:
c. Can be used only with scanning
Explanation:
Coarse Adjustment Knob is a large knob on each side of the microscope, with a smaller knob in the middle. This large knob is used to bring an object into close focus as it moves the stage up or down. The coarse-adjustment knob is used ONLY with the scanning or low-power objective lenses.