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Tema [17]
3 years ago
7

TRUE OR FALSE? The genetic code is determined by the SIZES of the nitrogen bases.

Physics
1 answer:
lidiya [134]3 years ago
5 0
False it is not determined by size
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A bus travels north on some busy city streets for 2.5 km, and a trip
d1i1m1o1n [39]

Answer:

V = 4.63 m/s

V = 11.31 m/s

Explanation:

Given,

The distance traveled by the bus, towards north, d = 2.5 km

                                                                                     = 2500 m

The time taken by the trip is, t = 9 min

                                                  = 540 s

The velocity of the bus,

                                       V = d / t

                                           = 2500 / 540

                                          = 4.63 m/s

At another  point, the bus travels at a constant speed of v = 18 m/s

Therefore the velocity becomes

                                                V = (4.63 + 18)/2

                                                   = 11.31 m/s

Hence, the velocity of the  bus, V = 11.31 m/s

8 0
3 years ago
. Find the weight (weight = mg) of a 17 kg crate of books.
White raven [17]

Answer:

It is 37.4786

5 0
2 years ago
A truck is moving around a circular curve at a uniform velocity of 13 m/s. If the centripetal force on the truck is 3,300 N and
Paladinen [302]
Answer: Option B.

Since here the truck is moving on a circular track, it will experience centripetal force.

F(centripetal) = m × acc 
or 
r = \frac{m v^{2}}{F}

where r is the radius of the track. 
m is the mass of truck
v is the speed  of the truck. 
Given: v = <span>13 m/s
m = </span><span>1,600 kg
</span>F = 3300 Newton

To find = radius of track=?
r = \frac{m v^{2} }{F}
r = \frac{1600*13*13}{3300}
r = 81.94 m
Therefore, radius of track is 81.94 m
4 0
3 years ago
Read 2 more answers
A very small object carrying -7 μC of charge is attracted to a large, well-anchored, positively charged object. How much kinetic
miss Akunina [59]

Answer:

ΔK.E = 14 nJ

Explanation:

Solution:

- The charge that moves under the influence of an Electric Field produced between a potential difference (V) stores electric potential energy U within that is converted to kinetic energy.

- We will use conservation of energy on the system that contains the charged particle with charge q loses its electric potential energy U as it moves towards positively charged object that converts into a gain in Kinetic energy of the charged particle ΔK.E:

                                 ΔK.E = U

Where,

                                 U = V*q

                                 ΔK.E = V*q

                                 ΔK.E = (7*10^-6)*(2*10^-3)

                                 ΔK.E = 14 nJ

- The gain in kinetic energy is 14 nJ.

7 0
3 years ago
A dentist’s drill starts from rest. After 3.20 s of constant angu-lar acceleration, it turns at a rate of 2.51 3 104 re v/m i n.
Gekata [30.6K]

Answer:

ΔTita = 4205.6 rad

Explanation:

w_{i} means initial angular velocity, which is 0 rev/min

w_{f} means final angular velocity, which is 2.513*10^{4}rev/min

t means time t= 3.20 s

one revolution is equivalent to 2πrad so the final angular velocity is:

w_{f} = (2π/60) *2.513*10^{4} rad/s

w_{f}= 2628.5 rad/s

so the angular acceleration, α will be:

α = 2628.5 rad/s / 3.20 s

a = 821.40 rad/s^{2}

so the rotational motion about a fixed axis is:

w^{2} _{f} =w^{2} _{i} + 2αΔTita    where ΔTita is the angle in radians

so now find the ΔTita the subject of the formula

ΔTita = \frac{w^{2} _{f}-w^{2} _{i}  }{2a}

ΔTita = ((2628.5)^{2} - (0 rev/min)^{2}) / 2* 821.40

ΔTita = 4205.6 rad

7 0
3 years ago
Read 2 more answers
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