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vaieri [72.5K]
3 years ago
9

When using a Microscope's high power objective the course adjustment knob:

Physics
2 answers:
djverab [1.8K]3 years ago
8 0

Answer:

The correct option is;

d. Objective should not be used

Explanation:

The coarse-adjustment knob is the large knob at the base of the Microscope close to the smaller fine-adjustment knob. The coarse-adjustment knob is meant to aid in the movement of the object into proper focus either upwards or downwards and is only meant to be used with the scanning, low power objective lenses.

When using the Microscope's high power objective lens, the field of view is narrower as such only the fine adjustment knob should be used.

kvasek [131]3 years ago
5 0

Answer:

c. Can be used only with scanning

Explanation:

Coarse Adjustment Knob is a large knob on each side of the microscope, with a smaller knob in the middle. This large knob is used to bring an object into close focus as it moves the stage up or down. The coarse-adjustment knob is used ONLY with the scanning or low-power objective lenses.

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At 9:13AM a car is traveling at 35 miles per hour. Two minutes later, the car istraveling at 85 miles per hour. Prove that are s
andreyandreev [35.5K]

Answer:

There is at least one instant which instantaneous acceleration is equal to average acceleration. a = 1500\,\frac{km}{h^{2}}.

Explanation:

The average acceleration experimented by the car is:

\bar a = \frac{85\,\frac{km}{h} - 35\,\frac{km}{h} }{\frac{2}{60}\,h }

\bar a = 1500\,\frac{km}{h^{2}}

According to the Rolle's Theorem, there is at least one instant t so that instantaneous acceleration equal to average acceleration for the analyzed interval. That is to say:

v'(c) = \frac{v(\frac{2}{60} )-v(0)}{\frac{2}{60}-0}

If car is accelerating at constant rate, instantaneous acceleration coincides with average acceleration for all instant t. Then, instantaneous acceleration is:

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3 years ago
You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is
Arlecino [84]

Answer:

a) v=0.5405\ m.s^{-1}

b) v_p'=0.1143\ m.s^{-1}

Explanation:

Given:

mass of ball, m_b=4\ kg

initial speed of the ball, v_b=10\ m.s^{-1}

mass of the person, m_p=70\ kg

a)

Using the conservation of linear momentum:

When the person catches the ball, assuming that the person catches it with an impact without absorbing the shock.

m_b.v_b=(m_b+m_p)v

4\times 10=(4+70)\times  v

v=0.5405\ m.s^{-1}

b)

When the ball hits the person and bounces off with the velocity of v_b'=8\ m.s^{-1}.

Using the conservation of linear momentum:

m_b.v_b+m_p.v_p=m_b.v_b'+m_p.v_p'

where:

v_b'= final speed of the ball after collision

v_p'= final speed of the person after collision

v_p= initial velocity of the person = 0

putting the respective values in the above eq.

4\times 10+0=4\times 8+70\times v_p'

v_p'=0.1143\ m.s^{-1}

8 0
3 years ago
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kirill [66]
I believe the answer is C

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3 years ago
Write down two advantages of parallel combination ​
Simora [160]

Answer:

In parallel combination each appliance gets the full voltage.

If one appliance is switched on/of others are not affected.

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Answer:

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