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3 years ago

When using a Microscope's high power objective the course adjustment knob:

Physics

2 answers:

djverab [1.8K]3 years ago

8 0

Answer:

The correct option is;

d. Objective should not be used

Explanation:

The coarse-adjustment knob is the large knob at the base of the Microscope close to the smaller fine-adjustment knob. The coarse-adjustment knob is meant to aid in the movement of the object into proper focus either upwards or downwards and is only meant to be used with the scanning, low power objective lenses.

When using the Microscope's high power objective lens, the field of view is narrower as such only the fine adjustment knob should be used.

kvasek [131]3 years ago

5 0

Answer:

c. Can be used only with scanning

Explanation:

Coarse Adjustment Knob is a large knob on each side of the microscope, with a smaller knob in the middle. This large knob is used to bring an object into close focus as it moves the stage up or down. The coarse-adjustment knob is used ONLY with the scanning or low-power objective lenses.

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An object is dropped from a height H. During the final second of its fall, it traverses a distance of 53.2 m. What was H? An obj

Serhud [2]

Answer:

H = 171.90 m

Explanation:

given data

distance = 53.2 m

height = H

to find out

height H

solution

we know height is here H = $\frac{1}{2} gt^2$ ......................1

here t is time and a is acceleration

we find t first

we know during time (t -1) s , it fall distance (H - 53.2) m

so equation of distance

$H - 53.2 = \frac{1}{2} g (t-1)^2$

$H - 53.2 = \frac{1}{2} g (t^2-2t+1)$

$H - 53.2 = \frac{1}{2} gt^2-gt+\frac{1}{2} g$ ................2

now subtract equation 2 from equation 1 so we get

$H - (H - 53.2) =\frac{1}{2} gt^2- (\frac{1}{2} gt^2-gt+\frac{1}{2} g)$

53.2 = gt - $\frac{1}{2} g$

53.2 = 9.81 t - $\frac{1}{2} 9.8$

t = 5.92 s

so from equation 1

H = $\frac{1}{2} (9.81)5.92^2$

H = 171.90 m

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3 years ago

The density of an object is 1.23 g/cm3. In which of the following materials will it float

Leviafan [203]

Citric Acid is the correct answer because it contains a density of 1.66 g/cm3, whereas water= 1.00 g/cm3, Olive oil= 0.93 g/cm3, Ethyl alcohol= 0.79 g/cm3

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3 years ago

Read 2 more answers

A solid concrete block weighs 140 N and is resting on the ground. Its dimensions are 0.370 m x 0.150 m x 0.0820 m. A number of i

belka [17]

Answer: 18 blocks in total ( 17 add to the original in contact with the ground)

Explanation:

The pressure on the face in contact with the ground ( we choose the face 0.15m x 0.082m)

Pressure= Force ( weigth) /Area

1 Atm = 101325 Pascal [N/ m^2]

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3 years ago

Why is it that when opening a tin milk, have to open two holes?

Oksi-84 [34.3K]

Answer:

so your milk is secured

Explanation:

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3 years ago

If a ping pong ball and a golf ball are both moving in the same direction with the same amount of kinetic energy, the speed of t

Liono4ka [1.6K]

If the kinetic energy of each ball is equal to that of the other,
then

(1/2) (mass of ppb) (speed of ppb)² = (1/2) (mass of gb) (speed of gb)²

Multiply each side by 2:

(mass of ppb) (speed of ppb)² = (mass of gb) (speed of gb)²

Divide each side by (mass of gb) and by (speed of ppb)² :

(mass of ppb)/(mass of gb) = (speed of gb)²/(speed of ppb)²

Take square root of each side:

√ (ratio of their masses) = ( 1 / ratio of their speeds)²

By trying to do this perfectly rigorously and elegantly, I'm also
using up a lot of space and guaranteeing that nobody will be
able to follow what I have written. Let's just come in from the
cold, and say it the clear, easy way:

If their kinetic energies are equal, then the product of each
mass and its speed² must be the same number.

If one ball has less mass than the other one, then the speed²
of the lighter one must be greater than the speed² of the heavier
one, in order to keep the products equal.

The pingpong ball is moving faster than the golf ball.

The directions of their motions are irrelevant.

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3 years ago