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mr Goodwill [35]
3 years ago
11

How do i find the finite approximation to estimate the area using the lower sum of 4 rectangles for f(x)= 4-x^2 between x=-2 and

x=2?
...?
Mathematics
1 answer:
nikitadnepr [17]3 years ago
7 0
The primary rectangle would be from - 2 to - 1. 
f(- 2) = 0 
f(- 1) = 2 
this rectangle has 0 stature, subsequently it has no territory. A = length * width = 0. 


second rectangle from - 1 to 0 
f(- 1) = 2 
f(0) = 4 
this rectangle has stature of 2 (the base). range = stature * width = 2 * 1 = 2

 third rectangle from 0 to 1 is the same 
A3 = 2 
fourth rectangle from 1 to 2 is the same as the first: 
A4 = 0 * 1 = 0 
Add up to range = A1 + A2 + A3 + A4 = 4
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Elsa saving money to buy a game so far she had saved $36 which is 3/4 of the total cost of the game how much does the game cost
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Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Can someone help me please????
liraira [26]
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Here X~ Binomial Distribution with n = 5 and p = 0.80.

the probability of her missing 3 (or more) free throws out of 5

= P ( X ≤ 2)

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=0.00032 + 0.0064 + 0.0512
<span>
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I hope my answer has come to your help. God bless and have a nice day ahead!
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A number cube is tossed 8 times. What is the probability that the cube never lands on 3?.
tino4ka555 [31]

The probability that the cube never lands on 3 is (D) 23.3%.

<h3>What is probability?</h3>
  • A probability formula can be used to calculate the likelihood of an occurrence by simply dividing the favorable number of possibilities by the entire number of possible outcomes.

To find the probability that the cube never lands on 3:

Given -

  • Number cube toss = 8

Required

  • Probability of not landing on 3.

First, we need to get the probability of landing on 3 in a single toss.

For a number cube,

  • n(3) = 1 and n(total) = 6

So, the probability is P(3) = 1/6

First, we need to get the probability of not landing on 3 in a single toss.

Opposite probability = 1.

  • So, P(3) = P(3') = 1.

Make P(3') the subject of the formula.

  • P(3') = 1 - P(3)
  • P(3') = 1 - 1/6
  • P(3') = 5/6

In 8 toss, the required probability is (P(3'))⁸

This gives:

  • P = (5/6)⁸
  • P = 390625/1679616
  • P = 0.23256803936

Approximate to 1 decimal place, P = 23.3%.

Therefore, the probability that the cube never lands on 3 is (D) 23.3%.

Know more about probability here:

brainly.com/question/25870256

#SPJ4

The correct question is given below:
A number cube is tossed 8 times. What is the probability that the cube never lands on 3?

A. 6.0%

B. 10.4%

C. 16.7%

D. 23.3%

5 0
1 year ago
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