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s2008m [1.1K]
3 years ago
8

A bag contains 42 cups of dog food. Your dog eats 2 1/3 cups of dog food 1 point

Mathematics
2 answers:
jek_recluse [69]3 years ago
7 0

Answer:

its 18 days

Step-by-step explanation:

what i did was divide 42 divided by 2

then i added 21 1/3 and got 18

Strike441 [17]3 years ago
4 0

Answer:

It will last 18 days.

Step-by-step explanation:

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There are seven roads that lead to the top of a hill. How many different ways are there to reach the top and then go back down?
rjkz [21]

Answer:

two I have no idea of the question

4 0
3 years ago
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Pensé dos números. Si los sumo obtengo 20. Si al doble del primer número le sumo 35 obtengo el segundo. ¿ qué número pensé?
SpyIntel [72]
For this case, the first thing we must do is define variables:
 x: first number
 y: second number
 We now write the system of equations:
 x + y = 20
 y = 2x + 35
 Solving the system we have:
 x = -5
 y = 25
 Answer:
 
The numbers are:
 
x = -5
 
y = 25
4 0
3 years ago
image Alan, Benton, Claire, and Dita divided the cost of throwing a party as shown in the circle graph above. If Dita spent $ 12
sdas [7]

Let total amount spent =x

Dita spent 35 % of total amount.

35% of x = 0.35x

So amount spent by Dita = 0.35x

% of money spent by Benton = 20 % of x = 0.2x

We are given that Benton spent $12 more than Claire,

so making equation we have ,

Money spent by Dita = Money spent by Claire +12

0.35x =0.2x +12

0.35x -0.2x = 12

0.5x =12

x=80

So total amount spent was $80.

Money spent by Benton = 0.2x = 0.2 * 80= $16

So amount spent by Benton is $16.



5 0
3 years ago
A set of equations is given below:
Tasya [4]

Answer:

The number of solutions to the given set of equations is 0.

Step-by-step explanation:

Number of solutions of a system of equations:

System of equations: ax = b

If a = 0 and b = 0, infinite solutions.

If a = 0 and b != 0, zero solutions.

If a != 0 and b != 0, one solution.

We are given the following system of equations:

y = 7x + 12

y = 7x + 2

So

7x + 12 = 7x + 2

7x - 7x = 2 - 12

0x = -10

a = 0, b != 0, so zero solutions.

The number of solutions to the given set of equations is 0.

6 0
3 years ago
Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess
Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2

4 0
3 years ago
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