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Akimi4 [234]
3 years ago
5

(49-1)=(10+6) Can you help me with this question?

Mathematics
2 answers:
Helga [31]3 years ago
8 0
That problem is false because the left hand and right hand side are different. Idk if this is correct or not but I recommend getting Photomath it’s free on the App Store and it will help with equations like these. (It’s where I got the answer to this problem ;)
sergey [27]3 years ago
7 0
Answer: No Solution
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Valerie drives 500 meters up a hill that makes an angle of 15degrees with the horizontal. To the nearest tenth of a meter, what
erastova [34]
The horizontal component can be calculated using:
500cos(15)
= 483.0 meters
The answer is A.
3 0
3 years ago
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5th grade math. Correct answer will be marked brainliest. Which boxes go where?
loris [4]

Answer:

.46 x 14 = 6.44

46 x 1.4 = 64.4

46 x 14 = 644

4.6 x 14 = 64.4

46 x .14 = 6.44

Step-by-step explanation:

3 0
3 years ago
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3- A rectangle has an area of 30 square meters arm a perimeter of 34 meters the dimensions , of the rectangle I 9 , a J v ft HA
Leto [7]
If you are looking for the answer to the question above you have to ask yourself what two numbers multiply to 30 and equal 17 when added up. We halve the perimeter to make this easier. So your answer is 15 and 2 because 15 *2=30. If the sides are 15 and 2 then, 15(2) +2(2)=34. There is your answer. 
4 0
3 years ago
Find the Two Values that x can have if X^2 -10=26​
Zolol [24]

Answer:

x1= -6 x2=6

Step-by-step explanation:

x^2-10 = 26

x^2 = 26 +10

x^2 = 36

x = sqrt(36)

x = -6 or x = 6 because both 6 and -6 squared are equal to 36

3 0
3 years ago
Read 2 more answers
A sample of 1200 computer chips revealed that 45% of the chips fail in the first 1000 hours of their use. The company's promotio
yaroslaw [1]

Answer:

z=\frac{0.45 -0.48}{\sqrt{\frac{0.48(1-0.48)}{1200}}}=-2.08

p_v = P(Z

So the p value obtained was a low value and using the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of chips that fail in the first 1000 hours of their use is not significantly less than 0.48.   

Step-by-step explanation:

Data given and notation

n=1200 represent the random sample taken

\hat p=0.45 estimated proportion of chips that fail in the first 1000 hours of their use

\mu_0 =0.48 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion si less then 0.48:  

Null hypothesis:p\geq 0.48  

Alternative hypothesis:p < 0.48  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion  is significantly different from a hypothesized value .

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.45 -0.48}{\sqrt{\frac{0.48(1-0.48)}{1200}}}=-2.08

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v = P(Z

So the p value obtained was a low value and using the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of chips that fail in the first 1000 hours of their use is not significantly less than 0.48.  

6 0
3 years ago
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