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dexar [7]
3 years ago
6

Determine the sum of the following arithmetic series: 3, 10, 17, 24, 498

Mathematics
1 answer:
shepuryov [24]3 years ago
6 0

Answer:

552

Step-by-step explanation:

when the sum of 3+10+17+24+498 is done it becomes 552

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Find the equation of the line passing through the points (3,-2) and (4,6) in slope intercept form.​
noname [10]

Hey!

------------------------------------------------

They already give us the slope, so we can solve the y-intercept.

We can use (3, -2).

y = 8x + b

-2 = 8(3) + b

-2 = 24 + b

-2 - 24 = 24 + b - 24

-26 = b

------------------------------------------------

Hence, the answer is \Large\boxed{\mathsf{y~=~8x~+~-26}}

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Hope This Helped! Good Luck!

4 0
3 years ago
Suppose that a cyclist began a 364 mi ride across a state at the western edge of the​ state, at the same time that a car traveli
maw [93]
The car's average rate  is 43.7 mph. The bicycle's average rate is 12.3 mph.

To get this solution, let the bicycle's average rate be (x) and the car's average rate be (x + 31.4) mph. 

Distance= Speed x Time
364 = (x + x + 31.4) 6.5
364 = (2x + 31.4) 6.5
364/6.5 = 2x + 31.4
56 = 2x + 31.4
56 - 31.4 = 2x
24.6 = 2x
24.6/2 = x
12.3 = x

x = 12.3 mph     
x+31.4 = 43.7 mph
6 0
3 years ago
What is the completely factored form of this polynomial?<br> 18x^3– 120x^2-42x
Vlada [557]

Answer:

6×(3×+1)(×-7)

Step-by-step explanation:

18×^3-120×^2-42×

=6×(3×+1)(×-7)

4 0
3 years ago
Read 2 more answers
I need help with these questions
Katen [24]
The answer is c! As CBA & ZXY is not only a full triangle, but its written incorrectly.

ABC → CBA
XYZ → ZYX (not ZXY)
8 0
2 years ago
What is the value of R
frutty [35]

Answer:

2.45 × 10^{6}

Step-by-step explanation:

using the rules of exponents

• \frac{a^{m} }{a^{n} } = a^{(m-n)}

• (a^m)^{n} = a^{mn}

evaluating the numerator

(3.8 × 10^{5})² = 3.8² × (10^5)^{2} = 14.44 × 10^{10}

R = \frac{14.44.10^{10} }{5.9.10^{4} }

  = \frac{14.44}{5.9} × \frac{10^{10} }{10^{4} }

  = 2.45 × 10^{6} ← to 2 dec. places




7 0
3 years ago
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