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dexar [7]
3 years ago
6

Determine the sum of the following arithmetic series: 3, 10, 17, 24, 498

Mathematics
1 answer:
shepuryov [24]3 years ago
6 0

Answer:

552

Step-by-step explanation:

when the sum of 3+10+17+24+498 is done it becomes 552

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What is the solution to the equation 6y –2(y + 1) = 3(y – 2) + 6?
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Answer: y=2

Step-by-step explanation:

Distribute the numbers -2 and 3...

6y-2y-2=3y-6+6

The -6 and 6 cancel each other out...

6y-2y-2=3y

Combine like terms....

4y-2=3y

Move 4y over....

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Multiply both sides by -1.....

2=y

That’s your solution! Hope this helps!

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After getting 5 new rocks, George gave half of his rock collection to Susan. If George gave Susan 36 rocks, which equation could
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31 rocks to start with

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Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is
Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

p=\dfrac{2}{3}

q=\dfrac{1}{3}

Now,

P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

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