Answer: B
Step-by-step explanation: Ez
Answer:
I only know number 5 so here it is
the solution for the left is: 2x6=12
the solution for the right is: 5x3+4x1=15+4=19
and the answers are: 1.12 . 2.19
Answer: See explanation
Step-by-step explanation:
1. ∠WOV and m∠30° are complementary angles so they should add up to 90°
∠WOV + 30 = 90
Subtract 30 from both sides
∠WOV = 60°
I used the relationship of complementary angles.
2. ∠YOZ and ∠WOV are vertical angles so they're congruent.
∠YOZ ≅ ∠WOV
∠YOZ ≅ 60°
∠YOZ = 60°
I used the relationship of vertical angles.
I hope this helped!
Answer:
When raising an expression of that format to any power, after grouping like terms, you'll always find that the odd numbered terms are positive, and the even numbered terms are negative.
For example:
(x - y)² = x² − 2xy + y²
(x - y)³ = x³ − 3x²y + 3xy² − y³
(x - y)⁴ =x⁴ − 4x³y + 6x²y² − 4xy³ + y⁴
etc.
The graphed polynomial seems to have a degree of 2, so the degree can be 4 and not 5.
<h3>
Could the graphed function have a degree 4?</h3>
For a polynomial of degree N, we have (N - 1) changes of curvature.
This means that a quadratic function (degree 2) has only one change (like in the graph).
Then for a cubic function (degree 3) there are two, and so on.
So. a polynomial of degree 4 should have 3 changes. Naturally, if the coefficients of the powers 4 and 3 are really small, the function will behave like a quadratic for smaller values of x, but for larger values of x the terms of higher power will affect more, while here we only see that as x grows, the arms of the graph only go upwards (we don't know what happens after).
Then we can write:
y = a*x^4 + c*x^2 + d
That is a polynomial of degree 4, but if we choose x^2 = u
y = a*u^2 + c*u + d
So it is equivalent to a quadratic polynomial.
Then the graph can represent a function of degree 4 (but not 5, as we can't perform the same trick with an odd power).
If you want to learn more about polynomials:
brainly.com/question/4142886
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