Answer:
The variable, y is 11°
Step-by-step explanation:
The given parameters are;
in triangle ΔABC; 
in triangle ΔFGH;
Segment 
= 14 Segment 
= 14
Segment 
= 27 Segment 
= 19
Segment 
= 19 Segment 
= 2·y + 5
∡A = 32° ∡G = 32°
∡A = ∠BAC which is the angle formed by segments = 14 and = 19
Therefore, segment = 27, is the segment opposite to ∡A = 32°
Similarly, ∡G = ∠FGH which is the angle formed by segments = 14 and = 19
Therefore, segment = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
≅ by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∴ = = 27° y definition of congruency
= 2·y + 5 = 27° by transitive property
∴ 2·y + 5 = 27°
2·y = 27° - 5° = 22°
y = 22°/2 = 11°
The variable, y = 11°
I think it’s 311.75?
i added the closing balances and divided by the 4 selected days
either that or 44.54 if you divide by 28 days of February instead…
i might be wrong though
Answer:
A. y = -2/3x + 2
Step-by-step explanation:
Your is to isolate the y. The first thing you would do is subtract the 2x,
2x + 3y = 6
-2x =
3y = -2x +6
then to isolate the ,y, you would next divide everything by 3, so that the ,y, stays by itself.
3y/3 = -2x/3 +6/3
Simplify,
y = -2/3x + 2
<span>16 6/9 inches < 16 16/18 inches
or
Perimeter of square clock < Perimeter of rectangular clock
First we would put convert the perimeter fractions into equivalent terms. So for the square clock, 16 6/9 inches becomes 16 12/18 inches (multiplying the fraction by 2/2). Now it is obvious that that the square clock at 16 12/18 inches has a smaller perimeter than the rectangular clock with a perimeter of 16 16/18 inches.</span>
