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3 years ago

What is the y-intercept of the linear equation x-1/2y=-6

Mathematics

1 answer:

Leona [35]3 years ago

4 0

Answer:

y=mx+b

-6=m(1/2)+b or

-6=1/2(m)+b

Step-by-step explanation:

y=-6. x= 1/2

-6=m(1/2)+b

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The mean height of a sample of 15-year-old boys is 175 centimeters, with a standard deviation of 10. For a sample of 15-year-old

Alina [70]

The equation for standard deviation is finding the mean of the numbers, subtracting each of the initial numbers by the mean, squaring each of the results, finding the mean of these results added together, then finding out the square root of the results added together.

The mean of 175 and 165 is 170, subtract 175 and 165 by 170, and you get 5 and -5 respectively. Then, square the results and you get 25 and 25.

Add the two numbers together (25 & 25) then find the square root of it, which is 7.07106781187, simplified to 7.07.

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3 years ago

The value of y varies directly with x. If x =3, then y=21. What is the value of x when y=105?

Goshia [24]

Answer:

x = 15

Step-by-step explanation:

given that y varies directly with x

mathematically we can express this as

y = k x , where k is a constant

step 1: find k

given x = 3 and y = 21

y = k x

21 = k (3)

k = 7

hence the equation becomes

y = 7 x

when y = 105,

105 = 7x

x = 105 / 7 = 15

3 0

3 years ago

PLEASE HELP! (Look at photo)

spayn [35]

Answer:

Starting from the one on the left.

Upper left:

145 degrees

Down left:

35 degrees

Down right:

145 degrees.

-------------

Now for the right image.

Upper left:

153 degrees

Down left:

27 degrees

Down right:

153 degrees

Step-by-step explanation:

Apply the same steps for the second image as for the first.

One thing to keep in mind is that a flat line (horizontal or vertical), as an angle of 180 degrees.

And another useful reminder is that opposed angles have the same degree.

Starting from the one on the left.

Upper left:

180 - 35 = 145 degree

Down left:

since it is opposed to the upper right angle which is 35 degrees this one is also equal to 35 degrees.

Down right:

since it is opposed to the upper left angle which is 145 degrees this one is also equal to 145 degrees.

You can always double check by making sure one flat side (left or right or up or down), is equal to 180 degrees.

example: on the right image, for the down part, I wrote as answers 27 degrees (for down left because it is opposed to upper right) and 153 degrees (for down right because it is opposed to upper left) => 153 + 27 = 180 degrees

8 0

3 years ago

The campsite is square in shape and has an area of 4225 m2. What is the length of the campsite?

ziro4ka [17]

65 x 65= 4,225 m²
hope it helps! (:

7 0

3 years ago

Read 2 more answers

Mystery Boxes: Breakout Rooms

ollegr [7]

Answer:

$\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}$

Step-by-step explanation:

Given

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {[ \ ]} \\ \end{array}$

Required

Fill in the box

From the question, the range is:

$Range = 60$

Range is calculated as:

$Range = Highest - Least$

From the box, we have:

$Least = 1$

So:

$60 = Highest - 1$

$Highest = 60 +1$

$Highest = 61$

The box, becomes:

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

From the question:

$IQR = 20$ --- interquartile range

This is calculated as:

$IQR = Q_3 - Q_1$

$Q_3$ is the median of the upper half while $Q_1$ is the median of the lower half.

So, we need to split the given boxes into two equal halves (7 each)

Lower half:

$\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } \\ \end{array}$

Upper half

$\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

The quartile is calculated by calculating the median for each of the above halves is calculated as:

$Median = \frac{N + 1}{2}th$

Where N = 7

So, we have:

$Median = \frac{7 + 1}{2}th = \frac{8}{2}th = 4th$

So,

$Q_3$ = 4th item of the upper halves

$Q_1$ = 4th item of the lower halves

From the upper halves

$\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

We have:

$Q_3 = 32$

$Q_1$ can not be determined from the lower halves because the 4th item is missing.

So, we make use of:

$IQR = Q_3 - Q_1$

Where $Q_3 = 32$ and $IQR = 20$

So:

$20 = 32 - Q_1$

$Q_1 = 32 - 20$

$Q_1 = 12$

So, the lower half becomes:

Lower half:

$\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {12 } & {15} & {18}& {[ \ ] } \\ \end{array}$

From this, the updated values of the box is:

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$