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MArishka [77]
3 years ago
15

Which type of learner learns best through hands-on activities?

Computers and Technology
2 answers:
Masteriza [31]3 years ago
6 0

The correct answer is D. Bodily/Kinesthetic

Explanation

Kinesthetic intelligence is a term used to refer to the ability of individuals to use the body to express feelings and ideas. Also, it refers to the ability to produce or transform things with your hands. It is the type of intelligence necessary to have a good performance in tasks such as sports, dance, arts, mechanics, surgical medicine, among others.

This concept is part of the theory of multiple intelligences proposed in 1983 by psychologist Howard Gardner, who stated that man's cognitive competence is best described with the term "intelligences." This concept encompasses the set of mental abilities, talents or abilities. So, the correct answer is D. Bodily/Kinesthetic

Mumz [18]3 years ago
3 0
Bodily/ kinesthetic.
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Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
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Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

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