Answer:
F(t) = (-6.00 N/s^2)t^2
a(t) = (-3.00 N/s^2)t^2
Because F = ma, the acceleration function is the force function divided by mass (3.50 kg). Because the force is acting to the left, a negative has been introduced.
Take the integral of the acceleration function with the power rule for integrals. Initial velocity is 8.00 m/s
∫a(t) dt=v(t)+v1
v(t)=(-1m/s^4)*t^3+9 m/s
Setting velocity equal to zero and solving for t.
v(t)=0
t^3=9s^3
t=∛9s
=2.08 s
The integral of velocity is position. The object begins at the origin so initial position is 0
∫v(t) dt= x(t)
x(t)=(-0.25m/s^4)*t^4+(9m/s)*t
Plugging the t from step 3 into the x(t) function from step 4. This is the answer to part a.
x(2.08)=14 m
plug 3.50 s into the velocity function from step 2. Speed is the absolute value of velocity. This is the answer to part b.
v(3.5)=(1 m/s^4)(3.5 s)^3+9 m/s
= -18 m/s
speed(3.5 s)=║v(3.5)║=18 m/s
The frequency, f, of a wave is the number of waves passing a point in a certain time. We normally use a time of one second, so this gives frequency the unit hertz (Hz), since one hertz is equal to one wave per second.
Answer:
200N
Explanation:
mass(m) = 10 kg
acceleration(a) = 20 m/s^2
Force = mass * acceleration
= 10*20
= 200 N
Force = 200N
Answer:
0.78 m
Explanation:
I just did a hw question for this its just 344 divided by 440
Answer:
The total number of oscillations made by the wave during the time of travel is 1.4 Oscillations. Strictly speaking, the number of complete oscillations is 1.
Explanation:
The required quantity is the number of complete oscillations made by the traveling wave. The amplitude time and frequency are not needed to calculate the number of oscillations as it is the ratio of the distance traveled to the wavelength( minimum distance that must be traveled to complete one oscillation) of the wave. So the total number of oscillations is 1.4 while the number of complete oscillations is 1 (strictly speaking). The detailed solution to this question can be found in the attachment below. Thank you!