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Charra [1.4K]
3 years ago
6

Use the H-R diagram to answer the following questions.

Physics
2 answers:
PtichkaEL [24]3 years ago
7 0

Answer:

What is the approximate temperature of the supergiant Betelgeuse?  

3000 K

Which star on this diagram is the most similar to the Sun in luminosity and temperature?

Centauri A

I am Lyosha [343]3 years ago
5 0

Answer: The answer is 3000 K and Centauri A.

Explanation:

Just did it and got it right ♡´・ᴗ・`♡

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the ratio of the velocity of light in a vacuum to its velocity in a specified medium.
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What is the domain theory of ferromagnetism?
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A region within a magnetic material in which magnetization is in a uniform direction this means the individual magnetic moments of the atoms are aligned with one another and they point the same direction. when cooled bwlow a temperature called the curie temperature the magnetization of a piece of ferromagnetic material.<span />
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Which property of a substance can be determined using a pH indicator?
Gekata [30.6K]

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Acidity

Explanation:

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An airplane was 300 km [N] of Toronto airport, 3 hours later the airplane 600 km [S]
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3 years ago
A coil has 400 turns and self-inductance 7.50 mH. The current in the coil varies with time according to i = 1680 mA2 cos [πt/(0.
zhannawk [14.2K]

Answer:

(a) 1.58 V

(b) 0.0126 Wb

(c) 0.0493 V

Solution:

As per the question:

No. of turns in the coil, N = 400 turns

Self Inductance of the coil, L = 7.50 mH = 7.50\times 10^{- 3}\ H

Current in the coil, i = 1680cos[\frac{\pi t}{0.0250}] A

where

i_{max} = 1680\ mA = 1.680\ A

Now,

(a)  To calculate the maximum emf:

We know that maximum emf induced in the coil is given by:

e = \frac{Ldi}{dt}

e = L\frac{d}{dt}(1680)cos[\frac{\pi t}{0.0250}]

e = - 7.50\times 10^{- 3}\times \frac{\pi}{0.0250}\times \frac{d}{dt}(1680)sin[\frac{\pi t}{0.0250}]

For maximum emf, sin\theta should be maximum, i.e., 1

Now, the magnitude of the maximum emf is given by:

|e| = 7.50\times 10^{- 3}\times 1680\times 10^{- 3}\times \frac{\pi}{0.0250} = 1.58\ V

(b) To calculate the maximum average flux,we know that:

\phi_{m, avg} = L\times i_{max} = 7.50\times 10^{- 3}\times 1.680 = 0.0126\ Wb

(c) To calculate the magnitude of the induced emf at t = 0.0180 s:

e = e_{o}sin{\pi t}{0.0250}

e = 7.50\times 10^{- 3}\times sin{\pi \times 0.0180}{0.0250} = 2.96\times 10^{- 4} =0.0493\ V

7 0
3 years ago
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