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laiz [17]
3 years ago
12

a coil of 40 henry inductance is connected in series with aresistance of 8ohm and the combination is joined to the terminals of

a 2 volt battery. the time constant of the circuit is?
Physics
1 answer:
Andreyy893 years ago
7 0

Answer: 5 seconds

Explanation:

Given the following :

Inductance (L) = 40 henry

Resistance = 8 ohms

The circuit given above is a Resistor - Inductor (RL) circuit network. The time constant of an RL circuit is the ratio of the circuit Inductance (L) and Resistance (R). Time constant is measured in seconds.

THAT IS;

Time constant = L / R

THEREFORE ;

Time constant = 40 / 8

Time constant = 5 seconds

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While driving his 600-kg ultra-compact electric car, a distracted driver starts crossing a drawbridge. Not realizing that the dr
stellarik [79]

Answer:

Explanation:

a )

weight of car = 600 kg .

According to Archimedes principle , for free floatation ,

weight of car = weight of displaced water

600 x 9.8 = v x 10³ x 9.8 , v is volume of water displaced and 10³ kg/ m³ is density of water.

v = .6 m³

required fraction

= .6 / 2

= .3

b )

Let mass of water entering before the start of sinking of car .

mass of maximum displaced volume of water by car = 2 x 10³m³.

(600 + m ) x g = 2 x 10³ x g         [   10³ is density of water    ]

600 + m = 2000

m = 1400 kg .  

4 0
3 years ago
Calculate the potential required to push eleven amperes through a 20 ohm resistance
den301095 [7]

Answer:

The answer is 220

Explanation:

Volts = current × resistance

Current = 11

Resistance = 20

Volts = 11 × 20

= 220

5 0
3 years ago
Read 2 more answers
Exercise 1 Electric Fields In this exercise, you will use a digital multimeter to collect voltage data to graph electric fields.
Lyrx [107]

Answer:

The answers are in the explanation section below

Explanation:

1) The generalization that can be made from the exploration is that as we move away from the positive electrode, the potential energy gets lower. If we move away from the negative electrode, then the potential energy becomes higher.

2) The positive test charge will have the least potential energy when it gets to the negative electrode point.

3) To move one electron 1m in a direction along one of the equal potential lines, there is no energy needed. Zero work will be required for a charge to move on the equipotential line.

4) If lightning strikes a tree 20m away, it would be better to face the tree or have our back facing the tree. This is because the equipotential line will be present at the point where our body stands, this will protect from electric shock.

The pattern to be sketched is attached.

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4 0
3 years ago
An applied force varies with position according to F = k1 x n − k2, where n = 3, k1 = 3.6 N/m3 , and k2 = 76 N. How much work is
aniked [119]

Answer:

The work done is 205 kJ.

Explanation:

Hi there!

Work can be calculated using the following equation:

W = F · Δx

Where:

W = work

F = applied force

Δx = displacement

In this case, the force varies with the position, so we can divide the traveled distance in very small parts and calculate the work done over each part of the trajectory. Then, we have to sum all the works and we will obtain the work done from the initial position (xi) to the final position (xf). This is the same as saying:

W = ∫ F · dx  

F = 3.6 N/m³ · x³ - 76 N

W = ∫ (3.6 x³ - 76)dx

W = 0.9 x⁴ - 76x

Evaluating from xi to xf:

W = 0.9 N/m³ (21.9 m)⁴ - 76 N · 21.9 m - 0.9 N/m³(5.41 m)⁴ + 76 N · 5.41 m

W = 205 kJ

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3 years ago
While on vacation, a student picks up surface rocks from around the world to add to her rock collection. The composition of her
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