1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Stels [109]
3 years ago
11

Electric force is only dependent on charge. true or false?

Physics
2 answers:
Kitty [74]3 years ago
5 0
Your answer is false.
konstantin123 [22]3 years ago
5 0
The answer is false. 
You might be interested in
ILL GIVE BRAINLIEST!! URGENT PLEASE HELP
anygoal [31]
I believe the answer is the second one.
6 0
3 years ago
Is a iron a conduction , raidition or convection
Masja [62]

conduction sdnoajndsojnfojanskfnijoaknfibas

3 0
3 years ago
An spring has a period of 4 seconds. What is its frequency?
trasher [3.6K]

Answer:

2Hz

Explanation:

Hope this helps

7 0
3 years ago
If you hold a 50 kilogram barbell above your head for 3 seconds and
aalyn [17]

Answer:

c

if you calculate the net force you get 490 N

3 0
3 years ago
an empty density bottle weighed 23.5 and 48.4g when filled with water .The empty bottle was partially filled with sand until and
gavmur [86]

Answer:

Density of Sand is 2.653g/cm^{3}.

Explanation:

Given Empty Density bottle weighs 23.5gm(W=23.5gm)

Weight of bottle when completely filled water=48.4gm

So amount of water required to fill the bottle=Weight of bottle filled with water-W

Amount of water required to fill the bottle(w_{max})=48.4gm-23.5gm

w_{max}=24.9g

Since we know density of water d_{w} =1g/cm^{3} and w_{max}

We can calculate volume of empty space in the bottle(V).

w_{max}=d_{w}\timesV

V=\frac{w_{max} }{d_{w} }

V=\frac{24.9}{1}

V=24.9 g/cm^{3}

Now bottle is partially filled with sand,and weight of bottle is (w_{s})36.5gm

So,

Amount of sand added (m_{s})=36.5-Weight of the bottle

m_{s}=13g

After filling the bottle with water again,the weight of the bottle becomes (W_{2}=56.5g)

Therefore,

amount of water added to the bottle of sand in grams = W_{2}-36.5gm

amount of water added =56.5g-36.5g

amount of water added =20g

As the density of water = 1g/cm^{3}

Amount of water (in grams )=Volume of water occupied

20=volume of water added

Therfore volume of water added to the sand filled bottle(V_{w})=20cm^{3}

As we know the total volume of the water bottle(V),

Volume of the sand occupied in the water bottle=V-V_{w}

V_{s}=24.9g-20g

V_{s}=4.9g

We know,

Density=Mass/Volume

Therefore,

density of sand = \frac{m_{s} }{V_{s} }

density of sand =\frac{13}{4.9}

density of sand = 2.653g/cm^{3}

8 0
3 years ago
Other questions:
  • Compute the kinetic energy of a proton (mass 1.67×10−27kg ) using both the nonrelativistic and relativistic expressions for spee
    14·1 answer
  • baseball is hit into the air at an initial speed of 37.2 m/s and an angle of 49.3 ° above the horizontal. At the same time, the
    15·1 answer
  • a certain car is capable of accelerating at a rate of 10.60m/s^2. how long does it take for this car to go from a speed of 55/mi
    11·1 answer
  • Mars has a mass of about 6.4 x 1023 kg, and its moon Phobos has a mass of about 9.6 x 1015 kg. If the magnitude of the gravitati
    15·1 answer
  • What is a complete wave?
    15·1 answer
  • Through what vertical height is a 50 N object moved if 250 J of work is done lifting it against the gravitational field of Earth
    15·1 answer
  • Planck's constant, h, is 6.626 x 10-34 js. the speed of light in a vacuum, c, is 3.00 x 108 m/s. calculate the frequency of a gr
    9·1 answer
  • Difference between relating velocity and angular velocity?​
    8·1 answer
  • What is the ƒ if v = 50 m/s and λ = 10 m?
    5·1 answer
  • FORCE AND DISPLACEMENT AT AN ANGLE A sailor pulls a boat a distance of 30.0 m along a dock using a rope that makes a 25.0° angle
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!