The person HAD homework 75/100 or 75%
the remaining days he did NOT have homework , which is 25/100 or 25%
Answer:
0.1111
Step-by-step explanation:
Given that you roll two dice.
the average of the high and low roll is exactly 3,
Since die can show only 1 to 6 we can say average can be 3 in each of the following case.
(1,5) (2,4) (3,3) (4,2) (5,1)
There cannot be any other combination to get average of 3.
Thus favourable events = 4
Sample space will have
(1,1)...(1,6)
(2,1)....
(6,1)...(6,6) i.e. 36
So probability that the average of the high and low roll is exactly 3
=
Volume:

<h2>
Explanation:</h2>
A composite figure is formed by two or more basic figures or shapes. In this problem, we have a composite figure formed by a cylinder and a hemisphere as shown in the figure below, so the volume of this shape as a whole is the sum of the volume of the cylinder and the hemisphere:

So:

From the figure the radius of the hemisphere is the same radius of the cylinder and equals:

And the height of the cylinder is:

So:

The volume of a hemisphere is half the volume of a sphere, hence:

Finally, the volume of the composite figure is:

<h2>Learn more:</h2>
Volume of cone: brainly.com/question/4383003
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