Evaluate 6(-3) -1-51+131= O 16 -10 -20
2 answers:
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Answer:
a) Right Tailed
b) p-value = 0.119
c) We fail to reject the Null Hypothesis()
Step-by-step explanation:
We have the following data:
Test Statistic = z = 1.18
Claim: p > 0.2
Part a) Type of Test
Remember that when there is Greater than, Lesser than or any synonymous word in the claim, this means that the test is one-tailed.
- Greater than word indicates a Right Tailed Test
- Lesser than word indicates a Left Tailed Test
Since, the claim is that p is greater than 0.2, the hypothesis test will be Right Tailed.
Part b) P-value
We have to find the p-value for the given test statistic. Since, the test statistic is a z-value we will use z-table to find the p-value for this score. Since, this z-score is for claim that p is greater than 0.2, so we will find the p-value(probability) of score being above 1.18
The p-value of z being greater than 1.18 comes out to be 0.119. i.e.
p-value = 0.119
Part c) Decision
Calculated p-value is 0.119 and significance level = 0.05. The rule is:
- If p value is equal to or lesser than the significance level, then we reject the null hypothesis
- If p value is greater than the significance level, then we fail to reject the null hypothesis
Since, in this case our p-value is greater than the significance level, we fail to reject the null hypothesis ().