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Pepsi [2]
3 years ago
9

Write the equation for a hyperbola that passes through the point (‐ 2, ‐ 3)?

Mathematics
1 answer:
n200080 [17]3 years ago
8 0
The equation of hyperbola can vary much from simple to complex equation. Since the information given from this question is not many, the equation probably was the simple one. 
Assuming that the hyperbola formula is y= x^2 +b, then the value of b where x=-2 and y=-3 would be:
y= x^2 +b
-3= (-2)^2 +b
-3= 4+b
b=-3 -4= -7

The equation would be: y= x^2 -7
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To solve this problem, draw the situation for a better comprehension:

As we can see, the situation describes a right triangle and we can use pythagorean theorem to solve it.

To do this, use the corresponding units.

For inches:

\begin{gathered} h=\sqrt[]{84^2-48^2} \\ h=\sqrt[]{7056-2304} \\ h=\sqrt[]{4752} \\ h=68.9 \end{gathered}

The suspect is 68.9 inches high.

Convert this height to feet:

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1 year ago
Graph x=5. Find and explain the intercepts.
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Answer:

How to Graph x=5

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Step-by-step explanation:

#graphtheline #slopeinterceptform #algebra

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3 years ago
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Which expression is NOT equivalent to 8 . -54?
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Y = -3x - 2 and 5x + 2y = 15
denis-greek [22]

Answer:

(-19, 55)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = -3x - 2

5x + 2y = 15

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                     5x + 2(-3x - 2) = 15
  2. Distribute 2:                          5x - 6x - 4 = 15
  3. Combine like terms:            -x - 4 = 15
  4. Isolate <em>x</em> term:                      -x = 19
  5. Isolate <em>x</em>:                               x = -19

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                    y = -3x - 2
  2. Substitute in <em>x</em>:                                     y = -3(-19) - 2
  3. Multiply:                                                y = 57 - 2
  4. Subtract:                                               y = 55
8 0
3 years ago
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