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Viefleur [7K]
3 years ago
11

Is (10,8), (12,4), (15,15), (9,4) a function

Mathematics
1 answer:
Zolol [24]3 years ago
3 0
Yes it is. In order for something to be a function, no X values can be the same, which is the case here.
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Hi, please help me with this thank you!
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What is a rule for the nth term of the sequence 1/2, 1/4, 1/6, 1/8, ...?
rewona [7]

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1/18

Step-by-step explanation:

the denominator is going up by 2s

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Kathy has savings a hundred thousand if she invested 100,000 in a saving fund thats adds 5% each year about how much will her sa
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Step-by-step explanation:

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3 years ago
Find the distance between the two points in simplest radical form <br> (4,6) and (-2,9)
MrRa [10]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{4}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{9})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{(-2-4)^2+(9-6)^2}\implies d = \sqrt{(-6)^2+3^2}\implies d = \sqrt{36+9} \\\\\\ d = \sqrt{45}\implies d = \sqrt{9\cdot 5}\implies d=\sqrt{3^2\cdot 5}\implies d = 3\sqrt{5}

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Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)
Amanda [17]

Answer:

f_x(x,y,z)=4\sin (y-z)

f_x(x,y,z)=4x\cos (y-z)

f_z(x,y,z)=-4x\cos (y-z)

Step-by-step explanation:

The given function is

f(x,y,z)=4x\sin (y-z)

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

f_x(x,y,z)=4(1)\sin (y-z)

f_x(x,y,z)=4\sin (y-z)

Differentiate partially w.r.t. y and x, z are constants.

f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)

f_y(x,y,z)=4x\cos (y-z)

Differentiate partially w.r.t. z and x, y are constants.

f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)

f_z(x,y,z)=4x\cos (y-z)(-1)

f_z(x,y,z)=-4x\cos (y-z)

Therefore, the first partial derivatives of the function are f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z).

4 0
3 years ago
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