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GuDViN [60]
3 years ago
9

In an isosceles triangle with two congruent sides, the angles across from the legs are called ________ angles.

Mathematics
2 answers:
yaroslaw [1]3 years ago
8 0

The angles across from the legs are called as \boxed{\text{\bf base angles}}.

Further explanation:

Consider \triangle\text{ABC} as an isosceles triangle whose sides are AB, BC, CA as shown in attached Figure 1.

In an isosceles triangle the two sides are equal and the angles corresponding to the opposite sides are equal.

In Figure 1 it can be seen that the side AB and BC are equal and \angle\text{ABC} and \angle\text{ACB} are also equal.

These two equal sides AB and BC are known as legs and the third side BC is base.

The angles \angle\text{ACB} and \angle\text{ABC} are called as the base angle and the third angle \angle\text{BAC} is the vertex angle.

As per the angle sum property in \triangle\text{ABC}, the sum of three angles is equal to 180^{\circ}.

The angles of \triangle\text{ACB} is calculated as,

\angle\text{ACB}+\angle\text{ABC}+\angle\text{CAB}=180^{\circ}

Thus, the angles across from the legs are called as \boxed{\text{\bf base angles}}.

Learn more:

1. A problem on triangles brainly.com/question/2992432

2. A problem on line brainly.com/question/1473992

3. A problem on permutation brainly.com/question/5199020

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Geometry

Keywords: Triangle, coordinate geometry, angles, sum, side, leg, equal, isosceles, base angle, vertex angle, corresponding sides, opposite sides.

strojnjashka [21]3 years ago
5 0

Answer:

The angles across from the legs are called base angles

Step-by-step explanation:

we know that

The isosceles triangle is a triangle with two equal angles and two equal sides

The two equal sides are called legs and the third side is called base

The two equal angles are called base angles and the third angle is called vertex angle

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miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

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3 years ago
Pls help asap I will mark brainlist
Luba_88 [7]

<u>Answer</u>:

A. y = \frac{-2}{3}x + 3

<u>Explanation</u>:

slope: \frac{y2-y1}{x2-x1}

         : \frac{1-3}{3-0}

         : \frac{-2}{3}

equation: y - y1 = m( x - x1 )

                y - 1 = \frac{-2}{3}( x - 3 )

                y = \frac{-2}{3}x + 3

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Recall Marginal Cost is the derivative of Total Cost, and Fixed Cost is the cost of producing zero units.
olga nikolaevna [1]

Answer:

The total cost of producing 91 units of ACME rocket fuel is $3999.99.

Step-by-step explanation:

The Marginal Cost is given by the following function

MC(q) = 200*(q+9)^{-5}

The total cost function is the integrative of the marginal cost function. So:

TC(q) = \int {MC(q)} \, dq

TC(q) = \int {200*(q+9)^{-5}} \, dq

TC(q) = -50*(q+9)^{-4} + K

In which K, the integrative constant, is the fixed cost. So K = 4000.

1. Find the total cost of producing 91 units of ACME rocket fuel.

This is TC(91).

So

TC(91) = -50*(91+9)^{-4} + 4000 = 3999.99

The total cost of producing 91 units of ACME rocket fuel is $3999.99.

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Answer:

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