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3 years ago

Question 2 Rewrite in simplest radical form 1 x −3 6 . Show each step of your process.

Mathematics

1 answer:

s2008m [1.1K]3 years ago

7 0

Answer:

√(x)

Step-by-step explanation:

(1)/(x^-(1/2)) that's 3 goes into -3 leaving 1 and goes into 6 leaving 2

1/2 is same as 2^-1

so therefore we can simplify the above as

x^-(-1/2)

x^(1/2)

and 4^(1/2)

is same as √(4)

so we conclude as

√(x)

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What is - 3/4 x (- 2/7) x 4/3? Explain your work

Naya [18.7K]

Hope this helped! the answer is 2^7

7 0

3 years ago

Points $M$, $N$, and $O$ are the midpoints of sides $\overline{KL}$, $\overline{LJ}$, and $\overline{JK}$, respectively, of tria

Ivan

The midpoint theorem states that the line joining the mid points of two sides of a triangle is parallel to the third and facing side and equal to half of the length of the third side

Based on the midpoint theorem, the area of triangle ΔLPQ is 63 square units

The reason the value of the area of triangle ΔLPQ as given above is correct is as follows:

The given parameters;

The midpoint of $\overline {KL}$ = M; The midpoint of $\overline {LJ}$ = N; The midpoint of $\overline {JK}$ = O

The midpoint of $\overline {NO}$ = P; The midpoint of $\overline {OM}$ = Q; The midpoint of $\overline {MN}$ = R

The area of triangle ΔPQR = 21

The required parameter:

Calculate the area of triangle ΔLPQ

Method:

The definition of midpoint, area ratio, and area of a triangle formula can be used to find the area of triangle ΔLPQ

Solution:

According to the midpoint theorem, we have;

$\overline {QR}$ = (1/2) × $\overline {NO}$

$\overline {PR}$ = (1/2) × $\overline {OM}$

$\overline {PQ}$ = (1/2) × $\overline {MN}$

Given that $\overline {QR}$ is parallel to $\overline {ON}$ , and $\overline {PR}$ is parallel to, we have;

∠MON = ∠PRQ

Similarly, we have, ∠MNO = ∠PQR

Therefore, ΔPQR is similar to triangle ΔMON, which is also similar to ΔJKS

The area of triangle ΔPQR = 21, by area ratio = (Side ratio)², we have;

The sides of ΔMON = 2 × The side length of ΔPQR

The area of triangle ΔMON = 2² × The area of ΔPQR

∴ The area of triangle ΔMON = 4 × 21

Similarly the area of ΔJKS = 4 × 4 × 21

PQ = JK/4

The area of LPQ = (1/2) × PQ × h

h = (3/4×JL) × sin(x°)

∴ The area of LPQ = (1/2)×JK/4×(3/4×JL) × sin(x°)

However; (1/2)×JK×JL× sin(x°) = Area of ΔJKS = 4 × 4 × 21

Therefore;

The area of ΔLPQ = (Area of ΔJKS)/4×(3/4) = (4 × 4 × 21)/4×(3/4) = 63

The area of triangle ΔLPQ = 63 square units

Learn more about the midpoint theorem here:

brainly.com/question/15227899

8 0

3 years ago

How do i do this? I dont really know where to start

Alex787 [66]

Well, I don’t necessarily remember how to sketch a plane. However, I can help get you started by defining some words they use and hopefully you will be able to do this on your own!

So this plane is made up of three points, names E, D and B. (Edit: This plane may be made up of four points, because of point A.)

E and B are collinear with A. This basically means that they all are on the same line.

D is a vertex. This basically means that it is a dot that these two lines called rays will shoot out of it. I will attach a picture of a vertex.

CD and FD are called rays. See those little lines above them? I’ll be sure to attached another image so that you know what I’m taking about. Anyway, that means they are rays. Rays are like never ending lines; they start at a point and the line will go on for infinity.

(Edit: where did the point f come from? I really wish you would have attached the full picture...)

Whelp, that’s all I’ve got! Good luck!!

(Edit: looks like I can only attach one picture...I’ll comment the other.)