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Lerok [7]
3 years ago
15

The gym teacher has $250 to spend on volleyball equipment. She buys 4 volleyball nets for $28 each. Volleyballs cost $7 each. Ho

w many volley balls can she buy
Mathematics
1 answer:
pav-90 [236]3 years ago
4 0

Answer:

The maximum number of volleyballs that she can buy is 19

Step-by-step explanation:

Let

x ----> the number of volleyballs

we know that

The cost of each volleyball net ($28) by the number of volleyball nets (4) plus the cost of each volleyball ($7) multiplied by the number of volleyballs (x) must be less than or equal to $250

so

The inequality that represent this situation is

28(4)+7x\leq 250

Solve for x

112+7x\leq 250

subtract 112 both sides

7x\leq 250-112

7x\leq 138

Divide by 7 both sides

x\leq 19.7

therefore

The maximum number of volleyballs that she can buy is 19

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Maslowich
<h3><u>Given Information :</u></h3>

  • Length of parallel sides = 60 ft and 40 ft
  • Height of the trapezoid = 30 ft

<h3><u>To calculate :</u></h3>

  • Area of the trapezoid.

<h3><u>Calculation :</u></h3>

As we know that,

\bigstar \: \boxed{\sf {Area_{(Trapezium)} = \dfrac{1}{2} \times ( a + b) \times h}} \\

  • a and b are length of parallel sides.
  • h denotes height.

<em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>valu</em><em>es</em><em>,</em><em> </em><em>we</em><em> </em><em>get</em><em> </em>:

\longmapsto Area = \sf \dfrac{1}{2} × ( 60 + 40 ) × 30 ft\sf ^2

\longmapsto Area = \sf \dfrac{1}{2} × 100 × 30 ft\sf ^2

\longmapsto Area = 1 × 100 × 15 ft\sf ^2

\longmapsto Area = 100 × 15 ft\sf ^2

\longmapsto <u>Area = 1500 ft</u>\sf ^2

Therefore,

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6 0
2 years ago
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Answer:

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Step-by-step explanation:

if you continue drawing the top purple line you will have a triangle with three angles

70° ; is given

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180-70-40 = 70°; because sum of angles in a triangle is 180°

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disa [49]

Answer:

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Step-by-step explanation:

Data

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Process

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