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scoray [572]
3 years ago
8

(6x - 5y = 34 Lin is solving this system of equations: 3x +2y = 8 She starts by rearranging the second equation to isolate the y

variable: y = 4-1.5x. She then substituted the expression 4 - 1.5x for y in the first equation, as shown: 6x - 5(4- 1.5x) 6x - 20 – 7.5x -1.5x 34 = 34 = 54 = -36 Where did Lin go wrong when solving this problem?​
Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0

Answer:

It is a little hard to see where your steps are for the equation, but x = 4, and I will explain:

Step-by-step explanation:

We know y = -1.5x +4, so we plug that into the equation

6x - 5(-1.5 + 4) = 34

6x +7.5x - 20 = 34    Here we distributed the -5 into the parenthesis.

13.5x -20 = 34

13.5 = 54

x = 4

Hope this helps!

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for the sum where the initial value is a₁ and the common ratio is r and the term is n

S_n= \frac{a_1(1-r^n)}{1-r}

common ratio is -3
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first term is -5
and we want the 8th term

S_8= \frac{-5(1-(-3)^8)}{1-(-3)}
S_8= \frac{-5(1-6561)}{1+3}
S_8= \frac{-5(-6560)}{4}
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the sum is 8200
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Answer:

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Step-by-step explanation:

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A sneaker company can make 50 pairs of sneakers for every 6 yards of material. Make a table to show the relation between materia
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A sneaker company can make 50 pairs of sneakers for every 6 yards of material.

Then in each case you can consider proportion.

1. 50 pairs -- 6 yards,

80 pairs -- x yards.

Mathematically,

\dfrac{50}{80}=\dfrac{6}{x},\\ \\x=\dfrac{80\cdot 6}{50}=9.6\ yards.

2. 50 pairs -- 6 yards,

100 pairs -- x yards.

Mathematically,

\dfrac{50}{100}=\dfrac{6}{x},\\ \\x=\dfrac{100\cdot 6}{50}=12\ yards.

3. 50 pairs -- 6 yards,

120 pairs -- x yards.

Mathematically,

\dfrac{50}{120}=\dfrac{6}{x},\\ \\x=\dfrac{120\cdot 6}{50}=14.4\ yards.

4. 50 pairs -- 6 yards,

140 pairs -- x yards.

Mathematically,

\dfrac{50}{140}=\dfrac{6}{x},\\ \\x=\dfrac{140\cdot 6}{50}=16.8\ yards.

Thus, the table is

\begin{array}{cc}\text{Pairs}&\text{Yards}\\50&6\\80&9.6\\100&12\\120&14.4\\140&16.8\end{array}

The domain of the relation is the set \{50,80,100,120,140\} and the range of the relation is \{6,9.6,12,14.4,16.8\}.See attached diagram for the graph of the relation.

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