Square root of 81 minus square root of negative 48 answer in a + bi form

Mathematics

1 answer:

galina1969 [7]3 years ago

4 0

Answer:

9-6.92820323i Nothing else can be done.

Step-by-step explanation:

-48 is not a perfect square but 81 is a square. When you try to square -48 it comes to be 6.92820323i.

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Karen spent 7/10 hour reading and 3/5 hours writing in her journal how much longer did karen spend reading than writing in her j

STatiana [176]

Answer: 1/10

Step-by-step explanation:

From the question, we are informed that Karen spent 7/10 hour reading and 3/5 hours writing in her journal.

To calculate how much longer karen spent reading than writing in her journal, we have to subtract 3/5 from 7/10. This will be:

= 7/10 - 3/5

Note that the lowest common multiple of 5 and 10 is 10.

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Root 3 cosec140° - sec140°=4 prove that

Lorico [155]

Answer:

Step-by-step explanation:

We are to show that $\sqrt{3} cosec140^{0} - sec140^{0} = 4\\$

Proof:

From trigonometry identity;

$cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}$

$\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\$

From trigonometry, 2sinAcosA = Sin2A

$= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\= \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2 \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}$