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3 years ago

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A student is trying to solve the system of two equations given below: Equation P: y + z = 6 Equation Q: 8y + 7z = 1 Which of the

following is a possible step used in eliminating the y-term?
A. (y + z = 6) ⋅ −8
B. (y + z = 6) ⋅ 7
C. (8y + 7z = 1) ⋅ 7
D. (8y + 7z = 1) ⋅ 8

2 answers:

Leto [7]3 years ago

5 0

Answer:

a. y + z = 6 * -8

Step-by-step explanation:

i took the test

Sergeeva-Olga [200]3 years ago

4 0

<span>P: y + z = 6
Q: 8y + 7z = 1

A. This makes y = -8Y which will eliminate the "y"'s when the equations are added.

</span>

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Find the simple interest on a loan of $45,000 for 5 years at 3%.

Tasya [4]

Answer:

51,750

Step-by-step explanation:

45,000x.03=1,350

1,350x5=6750

45,000+6750=51,750

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3 years ago

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Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C

Lesechka [4]

Answer:

Solution : $-\frac{3}{4}-\frac{3}{4}i$

Step-by-step explanation:

$-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]$

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

$\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}$

= $-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)$ ÷ $2\sqrt{2}\left(0-1\right)i$

= $3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right)$ ÷ $-2\sqrt{2}i$

= $\frac{3\left(1-i\right)}{\sqrt{2}}$ ÷ $2\sqrt{2}i$ = $-3-3i$ ÷ $4$ = $-\frac{3}{4}-\frac{3}{4}i$

As you can see your solution is the last option.

3 0

3 years ago

I only need 12 and 17, first good response i will give brainliest please i’m desperate

Mumz [18]

Answer:

$\textsf{12.} \quad y = 6x - 5$

$\textsf{17.} \quad y=-\dfrac{1}{4}x-2$

Step-by-step explanation:

<h3><u>Question 12</u></h3>

Find the slope of the line by substituting two points from the given table into the slope formula.

<u>Define the points</u>:

Let (x₁, y₁) = (2, 7)
Let (x₂, y₂) = (3, 13)

$\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{13-7}{3-2}=\dfrac{6}{1}=6$

Substitute the found slope and point (2, 7) into the point-slope formula to create an equation of the line:

$\implies y-y_1=m(x-x_1)$

$\implies y-7=6(x-2)$

$\implies y-7=6x-12$

$\implies y=6x-5$

<h3><u>Question 17</u></h3>

Given:

f(4) = 3
f(0) = -2

Therefore, two points on the line are:

(4, -3)
(0, -2)

The y-intercept is the y-value when x = 0.

Therefore, the y-intercept of the line is -2.

$\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}$

Substitute the y-intercept and the point (4, 3) into the slope-intercept formula and solve for <em>m</em> to find the slope:

$\implies y=mx+b$

$\implies -3=m(4)-2$

$\implies -1=4m$

$\implies m=-\dfrac{1}{4}$

Therefore, the equation of the line is:

$y=-\dfrac{1}{4}x-2$

7 0

1 year ago

Please help ill mark brainlist!!!

FromTheMoon [43]

Answer:

1/4 or 25%

Step-by-step explanation:

5 0

3 years ago

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Please help and show work on paper please

jasenka [17]

You learn more from failure than from success. Don’t let it stop you. Failure builds character.

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3 years ago