Answer:
The gradient of the straight line that passes through (2, 6) and (6, 12) is 
.
Step-by-step explanation:
Mathematically speaking, lines are represented by following first-order polynomials of the form:
(1)
Where:
- Independent variable.
- Dependent variable.
- Slope.
- Intercept.
The gradient of the function is represented by the first derivative of the function:
Then, we conclude that the gradient of the staight line is the slope. According to Euclidean Geometry, a line can be form after knowing the locations of two distinct points on plane. By definition of secant line, we calculate the slope:
(2)
Where:
, 
- Coordinates of point A.
, 
- Coordinates of point B.
If we know that 
and 
, then the gradient of the straight line is:
The gradient of the straight line that passes through (2, 6) and (6, 12) is .
Answer:
1/3
Step-by-step explanation:
Gradient=3/9=1/3
Ok
Sulition because I said do
11. 8 * 18 =
144 in³, Option D
12. Half the height of 8 cm is 4 cm. Volume = 4 * 6 * 10 =
240 cm³, Option D
13. Double the dimensions you get 8 cm for the height, 6 cm for the radius. Then plug in. V = pi * (6)² * 8 >> pi * 36 * 8 =
288pi or ≈ 904.78, Option C
14. Half of all the dimensions are 1 in, 4 in, and 3 in. 1 * 4 * 3 =
12 in³, Option B
15.
>> 16x = 180 >> x = 11.25
so Option B
16. Option D, 10 cm.
17. Option C, 8.5 in
18. Option B. 10.2 km
19. Option D. 0.82
20. cos 30 = b / 11.5 >> b = 11.5(cos (30)) =
9.96 m, Option C.
1.) 9 - c < 2 , C = 7
Graph 7 on the number line.
2.) -3c > 15, C = -5
Graph -5 on the number line.
Hope this helps.
