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sashaice [31]
3 years ago
7

A balloon is negatively charged by rubbing and then clings to a wall. does this mean that the wall is positively charged? why or

why not?
Physics
2 answers:
s2008m [1.1K]3 years ago
5 0

Answer:

When you rub the ballon, it steals electrons from the surface of the thing that is used to rub it.

Now, the electrons are un the surface of the ballon, and when you put it near the wall, the electrons of the wall are repelled by the large amount of electrons in the ballon, leaving only the positive charge in the surface of the wall, this positive surface is atracted by the ballon (and the ballon by the positive surface) and this is why the ballon clongs to the wall.

Oliga [24]3 years ago
3 0
<span>No. The wall is neutral but when you rub the balloon it gains electrons making it negative. When it goes near the wall the electrons in the wall repel so that the protons which are positive attract to the negative balloon. It falls because the wall will take electrons from the balloon.

Hope this helps!</span>
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A 5 kg block is being pushed horizontally across a level surface at a constant velocity. What is the magnitude of the Normal for
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Answer:

50 N.

Explanation:

On top of a horizontal surface, the normal force acting on an object is equivalent to the force of gravity acting on the object. That is:

\displaystyle \begin{aligned} F_N = F_g & = ma \\ & = mg\end{aligned}

The mass of the block is 5 kg and the given force due to gravity is 10 N/kg. Substitute and evaluate:

\displaystyle F_N = F_g = (5\text{ kg})(10 \text{ N/kg}) = 50 \text{ N}

In conclusion, the normal force acting on the block is 50 N.

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How do I Change the following to decimal numbers.<br> a. 5.93 x 10-5
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A block of mass 1.5 hangs at the of end of a weight cord suspended from the ceiling.what is the tension in the cord, and with wh
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The tension in the cord is 14.7 N and the force of pull of the cord is 14.7 N, assuming the block is stationary.

<h3>What is the tension in the cord?</h3>

The tension in the cord is calculated as follows;

T = ma + mg

where;

  • a is the acceleration of the block
  • g is acceleration due to gravity
  • m is mass of the block

T = m(a + g)

T = 1.5(a + 9.8)

T = 1.5a + 14.7

Thus, the tension in the cord is (1.5a + 14.7) N.

If the block is at rest, the tension is 14.7 N.

<h3>Force of the force</h3>

The force with which the cord pulls is equal to the tension in the cord

F = T = m(a + g)

F = (1.5a + 14.7) N

If the block is stationary, a = 0, the tension and force of pull of the cord = 14.7 N.

Thus, the tension in the cord is 14.7 N and the force of pull of the cord is 14.7 N, assuming the block is stationary.

Learn more about tension here: brainly.com/question/187404

#SPJ1

4 0
1 year ago
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