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k0ka [10]
3 years ago
5

Blood takes about 1.65 s to pass through a 2.00 mm long capillary. If the diameter of the capillary is 5.00 μm and the pressure

drop is 2.85 kPa , calculate the viscosity of blood. Assume laminar flow.
Physics
1 answer:
Murrr4er [49]3 years ago
6 0

Answer:

Viscosity of blood will be 918.54\times 10^{-6}Pa-sec

Explanation:

We have given time to pass the capillary = 1.65 sec

Length of capillary L = 2 mm = 0.002 m

Pressure drop \Delta P=2.85kPa=2.85\times 10^3Pa

Diameter d=5\mu m=5\times 10^{-6}m

So radius r=\frac{5\times 10^{-6}}{2}=2.5\times 10^{-6}m

Velocity will be v=\frac{L}{t}=\frac{0.002}{1.65}=1.212\times 10^{-3}m/sec

We know that viscosity is given by \eta =\frac{r^2\Delta P}{8Lv}=\frac{(2.5\times 10^{-6})^2\times 2.85\times 10^3}{8\times 0.002\times 1.212\times 10^{-3}}=918.54\times 10^{-6}Pa-sec

Viscosity of blood will be 918.54\times 10^{-6}Pa-sec

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