A light bulb has a resistance of 5 ohms and a maximum current of 10 A. How much voltage can be applied before the bulb will brea
1 answer:
The maximum voltage which can be applied before the bulb will break is 50 Volts.
<u>Given the following data:</u>
- Resistance of light bulb = 5 Ohms
- Current = 10 Amps.
To find how much voltage can be applied before the bulb will break, we would apply Ohm's law:
Ohm's law states that at constant temperature, the current flowing through an electrical circuit is directly proportional to the voltage applied across the two terminals of the circuit and it's inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
<u>Where;</u>
- V is voltage measured in voltage.
- I is current measured in amperes.
- R is resistance measured in ohms.
Substituting the given parameters into the formula, we have;
×
<em>Voltage </em><em>=</em><em> 50 Volts.</em>
Therefore, the maximum voltage which can be applied before the bulb will break is 50 Volts.
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An astronaut inside a spacecraft, which protects her from harmful radiation, is orbiting a black hole at a distance of 120 km from its center. The black hole is 5.00 times the mass of the sun and has a Schwarzschild radius of 15.0 km. The astronaut is positioned inside the spaceship such that one of her 0.030 kg ears is 6.0 cm farther from the black hole than the center of mass of the spacecraft and the other ear is 6.0 cm closer.
What is the tension between her ears?
Would the astronaut find it difficult to keep from being torn apart by the gravitational forces?
Answer:
The tension between the ears = 2.07 KN
The astronaut will find it difficult to keep and will eventually be in trouble because the tension is now greater compared to the tension in the human tissues.
Explanation:
Given that:
Orbital radius of the spacecraft (R) = 120 Km = 120 × 10³ m
Mass of the black hole (m) =
where :
Then; we have:
Schwarzchild radius of the black hole
r - 15.0 km
Mass of each ear
Farther distance between one ear and the black hole (d) = 6.0 cm
= 0.06 m
Closer distance between the other ear and the black home is (d) 6.0 cm
= 0.6 cm
NOW, If we assume that the tension force should be T; then definitely the two ears will posses the same angular velocity .
The net force on the ear closer to the black hole will be:
The net force on the ear farther to the black hole is :
Equating equation (1) and (2) & therefore making (T) the subject of the formula; we have:
The tension between the ears = 2.07 KN
The astronaut will find it difficult to keep and will eventually be in trouble because the tension is now greater compared to the tension in the human tissues.