The maximum voltage which can be applied before the bulb will break is 50 Volts.
<u>Given the following data:</u>
To find how much voltage can be applied before the bulb will break, we would apply Ohm's law:
Ohm's law states that at constant temperature, the current flowing through an electrical circuit is directly proportional to the voltage applied across the two terminals of the circuit and it's inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
<u>Where;</u>
Substituting the given parameters into the formula, we have;
×
<em>Voltage </em><em>=</em><em> 50 Volts.</em>
Therefore, the maximum voltage which can be applied before the bulb will break is 50 Volts.
Read more: brainly.com/question/23754122
Answer:
t = 16.5s
Explanation:
Given parameters:
Acceleration = 3.1m/s²
Initial velocity = 0m/s
Final velocity = 51m/s
Unknown:
Time taken = ?
Solution:
To solve this problem we need to reiterate that acceleration is the rate of change of velocity with time.
So;
Acceleration =
v is the final velocity
u is the initial velocity
t is the time taken
So;
3.1 =
3.1t = 51
t = 16.5s
Answer:0.114 C
Explanation:
Given
Total 4.7 C is distributed in two spheres
Let and
be the charges such that
and Force between charge particles is given by
put the value of
thus