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3 years ago

Which of the following are homogeneous solutions?

Physics

1 answer:

lana [24]3 years ago

7 0

Answer:

salt water, air and vinegar are homogeneous solutions.

Explanation:

A solution which consists of particles of same proportion is known as a homogeneous solution. Whereas a solution which consists of particles of different proportion is known as a heterogeneous solution.

Salt and water are homogeneous solutions as salt completely disperses in water and forms a clear solution as the particles of salt and water are in proportion.

Air is composed of different gases like nitrogen, oxygen etc are all mixed in fixed ratio. Therefore, air is a homogeneous mixture.

Sand and water are heterogeneous solution as the ration of mixing is different and more over sand particles can be separated from water. Thus, it is not a homogeneous mixture.

Vinegar is also a homogeneous solution as it is composed of acetic acid and water which are mixed in fixed proportion.

Cement is a heterogeneous mixture as it is composed of a number of different substances mixed in different proportions.

Thus, we can conclude that salt water, air and vinegar are homogeneous solutions.

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When would you use a compound microscope?

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3 years ago

A bicycle has wheels of 0.70 m diameter. The bicyclist accelerates from rest with constant acceleration to 22 km/h in 10.8 s. Wh

Anna11 [10]

Answer:

$\alpha=0.16\frac{rad}{s^2}$

Explanation:

Angular acceleration is defined as the variation of angular speed with respect to time:

$\alpha=\frac{\omega}{t}$

The relation between the angular speed and the linear speed is given by:

$\omega=\frac{v}{r}$

Replacing (2) in (1):

$\alpha=\frac{v}{rt}$

We need to convert $\frac{km}{h}$ to $\frac{m}{s}$ :

$22\frac{km}{h}*\frac{1h}{3600s}*\frac{1000m}{1km}=6.11\frac{m}{s}$

Recall that:

$r=\frac{d}{2}=\frac{0.7m}{2}=3.5m$

Replacing:

$\alpha=\frac{6.11\frac{m}{s}}{(3,5m)(10.8s)}\\\alpha=0.16\frac{rad}{s^2}$

3 0

4 years ago

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riadik2000 [5.3K]

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3 years ago

Given: G = 6.67259 × 10−11 N m2 /kg2 . A 438 kg geosynchronous satellite orbits a planet similar to Earth at a radius 1.94 × 105

photoshop1234 [79]

Answer:

449.37412 N

Explanation:

G = Gravitational constant = 6.67259 × 10⁻¹¹ m³/kgs²

m = Mass of satellite = 438 kg

M = Mass of planet

T = Time period of the satellite = 24 h

r = Radius of planet = $1.94\times 10^8\ m$

The time period of the satellite is given by

$T=2\pi\sqrt{\frac{r^3}{GM}}\\\Rightarrow M=4\pi^2\frac{r^3}{T^2G}\\\Rightarrow M=4\pi^2\times \frac{(1.94\times 10^8)^3}{(24\times 3600)^2\times 6.67259\times 10^{-11}}\\\Rightarrow M=5.78686\times 10^{26}\ kg$

The gravitational force is given by

$F=G\frac{Mm}{r^2}\\\Rightarrow F=6.67259\times 10^{-11}\times \frac{5.78686\times 10^{26}\times 438}{(1.94\times 10^8)^2}\\\Rightarrow F=449.37412\ N$

The force acting on this satellite is 449.37412 N

3 0

3 years ago

Calculate the number of molecules/m3 in an ideal gas at stp.

vivado [14]

STP (Standard Temperature and Pressure) has the following conditions:

Temperature = 273.15 K = 0°C
Pressure = 101325 Pa = 101.325 KPa = 1 atm

We also know that 1 mole = 6.022x10^23 molecules

Using the ideal gas equation: PV=nRT

n/V = P/RT

molecules/V = P*6.022x10^23/RT
molecules/V = 101325 Pa (6.022x10^23 molecules/mole)/ (8.314 Pa-m3/mol-K)(273.15K)

molecules/V = 7.339x10^27 molecules/m^3 - Final answer

4 0

4 years ago