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3 years ago

Which of the following are homogeneous solutions?

Physics

1 answer:

lana [24]3 years ago

7 0

Answer:

salt water, air and vinegar are homogeneous solutions.

Explanation:

A solution which consists of particles of same proportion is known as a homogeneous solution. Whereas a solution which consists of particles of different proportion is known as a heterogeneous solution.

Salt and water are homogeneous solutions as salt completely disperses in water and forms a clear solution as the particles of salt and water are in proportion.

Air is composed of different gases like nitrogen, oxygen etc are all mixed in fixed ratio. Therefore, air is a homogeneous mixture.

Sand and water are heterogeneous solution as the ration of mixing is different and more over sand particles can be separated from water. Thus, it is not a homogeneous mixture.

Vinegar is also a homogeneous solution as it is composed of acetic acid and water which are mixed in fixed proportion.

Cement is a heterogeneous mixture as it is composed of a number of different substances mixed in different proportions.

Thus, we can conclude that salt water, air and vinegar are homogeneous solutions.

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Explanation:

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2 years ago

The barrel of a rifle has a length of 0.89 m. A bullet leaves the muzzle of a rifle with a speed of 620 m/s. What is the acceler

guapka [62]

Answer:

215955.06 m/s^2

Explanation:

length of barrel, s = 0.89 m

initial velocity of the bullet, u = 0 m/s

Final velocity of the bullet, v = 620 m/s

Let a be the acceleration of the bullet in the barrel

Use third equation of motion, we get

$v^{2}=u^{2}+ 2as$

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3 years ago

How do I calculate speed, velocity, and acceleration? I need the formulas too

vodomira [7]

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3 years ago

hi :) is it true that zero acceleration means the object can be moving at constant velocity or at rest?

nirvana33 [79]

Answer:

Explanation:

Please let me know if my answer is correct

7 0

3 years ago

Read 2 more answers

A bowling ball of mass m = 1.7 kg drops from a height h = 14.2 m. A semi-circular tube of radius r = 6.2 m rest centered on a sc

marshall27 [118]

Answer:

W_net = mg + 2mgh/r

Explanation:

The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.

Now, gravitational force is; F_g = mg

While centripetal force is; F_c = mv²/r

Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.

Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.

Thus;

F_c = 2mgh/r

Where;

m is ball mass

r is tube radius

h is fall height

Thus, the net force will be;

F_net = F_g + F_c

Now, Net force would be equal to the net weight that will be read on the scale.

Thus;

W_net = F_net = F_g + F_c

W_net = mg + 2mgh/r

8 0

3 years ago