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dalvyx [7]
3 years ago
7

a 150 kg object takes a 1.5 minute travel to a 2500 straight path it begins you trip at traveling 120 miles an hour and it decel

erates to a velocity of 20 miles an hour what is it acceleration
Physics
1 answer:
crimeas [40]3 years ago
5 0
I believe it’s acceleration is -1.11 m/s^2
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6 0
3 years ago
A machine, modeled as a simple spring-mass system, oscillates in simple harmonic motion. Its acceleration is measured to have an
ANTONII [103]

a=5000\dfrac{mm}{s}=5\dfrac{m}{s}

f=10{Hz}\Longrightarrow t=\dfrac{1}{10}s

a_{max}=\dfrac{50\frac{m}{s}}{\frac{s}{10}}\cdot\dfrac{1}{\sqrt{2}}=\dfrac{50\dfrac{m}{s^2}}{\sqrt{2}}\approx\boxed{35.4\dfrac{m}{s^2}}

Hope this helps.

r3t40

5 0
3 years ago
What kind of scattering (Rayleigh, Mie, or non-selective) would you expect to be most important when radiation of the specified
oee [108]

Answer:

hello your question is not properly arranged attached below is the arranged table and solution

answer : attached table below

Explanation:

Given data:

02 molecules size = 10^-10m

smoke particles size = 0.3 mm

cloud droplets size = 20 mm

Rain droplets size = 3 mm

Attached below is a table showing the kind of scattering that is expected to occur at various wave lengths

Note : For Rayleigh scattering the wave particle is smaller than the wave length while for Non-selective scattering the wave particle is greater than the wavelength.

and  For Mie scattering the wavelength is the same as the wavelength.

3 0
3 years ago
An experiment is conducted on a long straight wire of diameter d. A constant current is sent through the wire and the magnetic f
soldi70 [24.7K]

Answer:

D.

Explanation:

To solve the exercise it is necessary to apply the concepts related to the Magnetic Field described by Faraday.

The magnetic field is given by the equation:

B = \frac{\mu_0 I}{2\pi d}

Where,

\mu = Permeability constant

d = diameter

I = Current

For the given problem we have a change in the diameter, twice that of the initial experiment, therefore we define that:

B_1 = \frac{\mu_0 I}{2\pi d}

B_2 = \frac{\mu_0 I}{2\pi 2d}

The ratio of change between the two is given by:

\frac{B_2}{B_1} = \frac{\frac{\mu_0 I}{2\pi d}}{\frac{\mu_0 I}{2\pi 2d}}

\frac{B_2}{B_1} = \frac{d}{2d}

\frac{B_2}{B_1} = \frac{1}{2}

B_2 = B_1 \frac{1}{2}

Therefore the correct answer is D.

4 0
3 years ago
Can someone please help me with this
SashulF [63]
There’s no picture or question
3 0
3 years ago
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